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Aratos (260 B.C.) mentioned this object as "Little Mist", Hipparchus (130 B.C.) included this object in his star catalog and called it "Little Cloud" or "Cloudy Star." Ptolemy mentions it as one of seven "nebulae" he noted in his Almagest, and describes it as "The Nebulous Mass in the Breast (of Cancer)". According to Burnham, it appeared on Johann Bayer's chart (about 1600 A.D.) as "Nubilum" ("Cloudy" Object).
Galileo has first resolved this "nebulous" object, and reported: "The nebula called Praesepe, which is not one star only, but a mass of more than 40 small stars."
Originally posted by Diplomat
The "object" appears when he is viewing the planet Venus, correct? So how exactly could an entire galaxy, or even a star cluster be BETWEEN Earth and Venus?
Originally posted by greatlakes
Originally posted by Diplomat
The "object" appears when he is viewing the planet Venus, correct? So how exactly could an entire galaxy, or even a star cluster be BETWEEN Earth and Venus?
he pans up and down in the video you can see it if you download the vid...from the moon to venus and possibly to either Saturn or most likely to the M44 galaxy. It isnt 'between' anything, see my sky charts above post for your way around the sky on that date and time.
Originally posted by skychief
I might be way, way off here, but could it be something on the ground such as a camp fire? It looks like a fire plsating through tall grass or branches. With out day light pictures to compare it's really hard to get an idea of position. Interesting thread.
Originally posted by skychief
I might be way, way off here, but could it be something on the ground such as a camp fire?
Originally posted by IAttackPeople
Hey, greatlakes, great minds think alike, eh? Only I do not think we are seeing
M44, though. If that cluster were visible on the video I think we'd be seeing LOTS of stars. I still can't shake the "Venus behind a branch" feeling.
The published magnitudes of deep sky objects (nebulae, galaxies and star clusters) can be quite misleading when it comes to indicating observability. ... At a visual magnitude of 6.5, for example, one might be led to believe that NGC 7293 (the Helix Nebula) would be readily visible in an 8 inch telescope since such an instrument has a limiting magnitude of about 13.5. Experience proves otherwise. Although its published magnitude indicates that this object is bright, it is in fact one of the more difficult deep sky objects, comparable to the Owl Nebula, requiring the best of observing conditions and perhaps a nebula filter to render it visible. Much "fainter" objects such as M27 (the Dumbell Nebula) at magnitude 8 and M57 (the Ring Nebula) at magnitude 9 are spectacular in an 8 inch while the "brighter" Helix might be invisible. Why is it that a telescope capable of seeing a 13th magnitude star might have difficulty showing a 6.5 magnitude nebula? The answer is in the size of the object.
The published magnitudes of deep sky objects indicate integrated brightness, or the total brightness of the object squeezed down to a point. If one could squeeze the light of the Helix, which is 16 arc minutes, or 16 x 60 = 960 arc seconds, in diameter (almost one half the apparent size of the moon) down to a point, it would be concentrated to the brightness of a 6.5 magnitude star. Conversely, if one was to defocus a 6.5 magnitude star to an image size of 960", the defocused disk would hav e an apparent brightness equal to that of the Helix. The reason, therefore, that this nebula appears so dim, is that its available light is spread over a large area. Although many other readily visible objects might be fainter, they are generally s maller, so their total available light is more concentrated resulting in a higher surface brightness. The Ring Nebula, for example is 2.5 magnitudes fainter than the Helix, but at a diameter of approximately 70" is about 14 times smaller so its avai lable brightness is considerably more concentrated resulting in a higher surface brightness.
The surface brightness of an object is therefore directly related to two factors, (1) its size, or more correctly, its area, and (2) its total available light. If two objects were equally bright (same visual magnitude) but one was twice as large, the larger would appear four times fainter since the same amount of light is spread over an area four times larger. Note that area is proportional to the square of the diameter. An object three times larger would appear nine times fainter, and so forth.