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Originally posted by Jim Deardorff
I wish I could get a statement from Jeff saying that he understands that the length of a pendulum determines the time period of its swing. If he can understand that, he could go back and understand how Maccabee, in 2002, determined the approximate distance from the camera that an assumed model UFO would have been. It would also help if he were to read Maccabee's website article on this at: brumac.8k.com...
as well as my own at www.tjresearch.info/BillyYes.htm. He shouldn't mind reading Maccabee's article as it's written in sort of a pro-UFO-model tone.
Originally posted by Jim Deardorff
I wish I could get a statement from Jeff saying that he understands that the length of a pendulum determines the time period of its swing.
Originally posted by jritzmann
I think theyre going of speed of oscillation, which isnt a constant. The speed can vary greatly and the actual size and wieght of the model are just as you said, unknown.
Originally posted by Centrist
Originally posted by jritzmann
I think theyre going of speed of oscillation, which isnt a constant. The speed can vary greatly and the actual size and wieght of the model are just as you said, unknown.
Physics does dictate the the period of simple pendulum is defined by the length of the pendulum (assuming the mass is concentrated to a point source at the end of the string).
Here, we have a much tougher problem. The object's properties are unlikely to be accurately quantified using a simple pendulum model. Not only is the length of the string going to be indeterminate due to the unknown mass and mass distribution, but assuming that the object in question is a small model, then it will be greatly influences by wind resistance and induced motion from whatever is suspending the string supporting the model.
EDIT:
Another thought -- how do we know that the pendulum is only travelling in two-dimensions? If the pendulum is moving in a circular or elliptical pattern, then the period as seen in two dimensions will appear larger. Also, if the model is relatively large with respect to the diameter of the circular orbit (or semi-major axis of the elliptical orbit) than the apparent angle subtended by the object from the viewer's observation point will not change enough to be measurable on the film. Again, more variables that cannot be accounted for.
[edit on 12-1-2006 by Centrist]
Originally posted by jritzmann
I think theyre going of speed of oscillation, which isnt a constant. The speed can vary greatly and the actual size and wieght of the model are just as you said, unknown.
Originally posted by Centrist
Another thought -- how do we know that the pendulum is only travelling in two-dimensions? If the pendulum is moving in a circular or elliptical pattern, then the period as seen in two dimensions will appear larger. Also, if the model is relatively large with respect to the diameter of the circular orbit (or semi-major axis of the elliptical orbit) than the apparent angle subtended by the object from the viewer's observation point will not change enough to be measurable on the film. Again, more variables that cannot be accounted for.
[edit on 12-1-2006 by Centrist]
Originally posted by Jim Deardorff
To first approximation you find the string is, say 14 ft long, giving a model UFO to be about 1 ft wide and, say, 6 inches high.
Originally posted by Jim Deardorff
The period of the pendulum is practically the same whether in simple harmonic motion (back and forth) or circular or elliptical. E.g., see www.marcdatabase.com/~lemur/vk-pendulum.html
Originally posted by Mindsite
Along with Underground Video's statement is a photograph showing one of Billy Meiers alleged Pleiadian beamships taken in 1981. After computer enhancement and careful scrutiny, it has been shown the Beamship is really a miniature model made out of an upside-down cake pan, disconnected copper hose fitting, a bracelet, carpet tacks and various other identifiable objects.
Originally posted by Centrist
Originally posted by Jim Deardorff
To first approximation you find the string is, say 14 ft long, giving a model UFO to be about 1 ft wide and, say, 6 inches high.
I think it's much more likely at one-armed man holding a stick probably had a string about three feet long (I'm of the opinion that Billy was using a fishing rod or something similar -- very low weight and easily handled by one hand, despite its length). I would agree that the size of the object would likely be about 1 foot in diameter, given the widespread speculation that the craft is made from household objects, such as dishes, bowls, etc. Also, I don't see one-armed men climbing trees to hang their models, so a 14 foot length seems excessive.
...
Just out of curiosity, why choose a 14 foot string as the starting assumption?
Originally posted by Jim Deardorff
In order for your assumption to merit consideration, you'd need to assume that the film Meier shot was subsequently padded with repeated frames such that the film length would be about 2.3 times longer. Then everything would move correspondingly slower in the movie, and the pendular period would be about 1.9 sec. This then would be compatiible with a string about 3 ft long.
Originally posted by TerraX
Jim,
It seems the 'weddingcake' craft had a little damage.
www.tjresearch.info...
One of those golden bits is lying on the horizontal rim, left of center. Like it broke off.
Originally posted by jritzmann
...
BTW, that wedding cake outside the house shot. One only need to remember this: if the house is out of focus, and the ship is as large as they say, then whey is the entire far edge in as perfect focus as the front. It's total impossibility.
Not to mention this:
Just look at that texture match. The fine detail of the luggage clasp and fine edged collet. So obvious it makes one sick.
[edit on 13-1-2006 by jritzmann]