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Its simple physics.
This is not correct. The resistance of the floor is, generously, 5 times its own weight. The weight falling on it was at least 12 times the weight of a floor. So there is a net acceleration as result of gravity. Would you have placed the mass carefully on the floor instead of dropping it, the floor would also have failed and there would also have been acceleration. No impact forces here.
Originally posted by Darkwing01
Energy cannot be created or destroyed PLB.
The acceleration due to gravity is a constant in this equation.
When the top section is doing more work than the force of gravity alone could have done
The weight of the top section is much greater than the supports of a single floor can carry. When resistance is lower than gravitational load it means there is acceleration.
No, the top section did not fall on the lower support structure. This is an extremely unrealistic scenario, even impossible when there is tilt. But even without tilt, its like throwing a stool from 2 meters high on top of another stool that is upside down, with the legs damaged and twisted. Its not going to happen.
Originally posted by -PLB-
reply to post by Darkwing01
All evidence I know of shows that the top section indeed accelerated. Feel free to demonstrate me wrong.
Originally posted by spy66
LoL, Here we go again. You are suggesting that the top section is built a stronger than the bottom section.
The Bottom section is strong enough to hold the top section stationary. That is the first thing you have to think about.
The second is that; when the vertical support structure between top and bottom section collapse. You have two floors touching first. The bottom of the top section and the top of the bottom section. GET IT?
The floors in the bottom section are designed to hold down force. The floors in the top section are designed to hold down force, not up force. Now; the top section is coming down. Do you see the issue now?
Which floor is the weakest? The bottom of the top section floor or the top floor of the bottom section?
Further;
You are suggesting that the core of the top section is built stronger than the core on top of the bottom section. That is not the case. The bottom section is designed to hold the top section. The reason it is not able to hold the top section stationary is because, there is damage on the vertical structure "core + walls" at the impact point.
The core at the bottom of the top section is not any stronger than the core on top of the standing building.
There are two issues here:
1. Mass in motion hitting stationary mass.
2. A intact floor hitting another intact floor.
The floor(s) at the impact point are damaged. They are the cause for the collapse.
Funny that you deny this, Because the building is connected from the ground up.
At best the top section would slide of the core and than tilt. But if that is the case you have more issues with your theory. If you are suggesting that the core of the top section sidestepped of the core of the bottom section. You have to take a look that how large the core was. If the core of top section sidestepped of the bottom core. The top section would have fallen of to the side of the building.
Never at any moment can we observe the building sidestep of the core. We would be able to observe that.
The only thing we are able to observe is that the top section tilts to one side. And that is because it is collapsing down onto the core of the lower section.
Originally posted by -PLB-
reply to post by Bob Sholtz
So what do you think happens to your "equal and opposite reaction" when there are failed floors between the top and lower section?
Third law: The mutual forces of action and reaction between two bodies are equal, opposite and collinear.
All evidence I know of shows that the top section indeed accelerated. Feel free to demonstrate me wrong.
Originally posted by Darkwing01
Exactly PLB.
The fact that it accelerated shows that the lower structure was not able to even resist the static load, nevermind the dynamic.
Imagine a series of evenly spaced dominoes on a flat surface. How do you get the rate at which the domino chain get knocked down accelerate? Why, by knocking down bricks ahead of the front of course.
You cannot achieve acceleration in a natural collapse of this type, if you think you can you will need to show me that empirical proof. You can readily and demonstrably achieve it in a controlled demolition...edit on 22-9-2011 by Darkwing01 because: (no reason given)
I already answered this, and asked what your point is. So what that after initiation both the lower and upper floor failed? Why is that an issue?
Originally posted by Bob Sholtz
Originally posted by -PLB-
reply to post by Bob Sholtz
So what do you think happens to your "equal and opposite reaction" when there are failed floors between the top and lower section?
oh, it's not MY "equal and opposite reaction". it's newton's third law of motion.
Third law: The mutual forces of action and reaction between two bodies are equal, opposite and collinear.
taking into account the fire damaged floors in the fall would even further distance the results from what is physically possible. those floors would be soft, but collapse wouldn't happen at 9.8m/s^2. the top part of the towers shouldn't have even fallen at all.
you've already asked this question, a stalling tactic because you know you're wrong. it would lessen the mass of "T". it leaves us with an inescapable conclusion that most of the resistance for 90 floors was removed.
Originally posted by Cassius666
www.opednews.com...
High school teacher-level Physics calculations show Gravity ACTION on 9/11 Towers was 0.1 KiloTons of TNT-equivalent ENERGY, and then debris and dust erupted over 8.5 KiloTons of 'TNT' ENERGY in REACTION. No spin, FACT: 0.1 KT ACTION not equal 8.5 KT REACTION Who dunnit? ::::::::
Originally posted by Bob Sholtz
i'm still waiting for you to show me how my math is wrong.