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Originally posted by Theophoros
He is not the one that references a Black Carbon Star that came from another video - I personally took it to mean a Black Dwarf. That video just mentions a Dwarf Star but he says it must be one that is extremely cold.
This guy says pretty much the same thing as I do - says Elenin is a "Black Star" which, to me, is either a Black Carbon Star or a Black Dwarf.
Originally posted by Theophoros
At sundown on the west coast Elenin is west of us - that is when the meteorite was spotted...
Originally posted by v1rtu0s0
All i can say is...
Originally posted by Theophoros
But, hey, Elenin is just a wimpy dusty ice ball...
Originally posted by Highlander64
Originally posted by chr0naut
[
Ice = no magnetic field.
The fact that it has melted pretty much identifies that it is ice.
I often wonder about statements like this
how can ice melt in space?
as we understand space is a vacuum and heat is not transferred through a vacuum
when you are in a plane at 30,000 feet the air temperature is -1 c maximum on a hot sunny day
its colder than that on the top of mount everest in summer
the higher you go and the thinner the atmosphere the colder it gets
So then we experience heat because we have an atmosphere and radiation from the sun travels through the vaccum of space and accelerates molecules in the atmosphere - or perhaps it is an electrical force
regardless, without an atmosphere ice will not melt, so what causes a comet tail? Could it be some form of electrical interaction between the sun and the comet?
Originally posted by nenothtu
Originally posted by Theophoros
But, hey, Elenin is just a wimpy dusty ice ball...
Now you're getting it!
I don't know how I manage to get sucked into these Elenin threads. It's now the 15th. If the world is going to end at Elenin's hand on the 27th, that's only 12 days away. Shouldn't I be getting drunk, blowing off work, and going on a rampage or something right about now? I mean, what are they gonna do? give me life in prison?
Both calculations are easy to do for an astrophysicist, but ONLY if the exact angular sizes are available. Since we only have some crappy video frames to go by, the following mass calculation is only A ROUGH ESTIMATE!