It looks like you're using an Ad Blocker.
Please white-list or disable AboveTopSecret.com in your ad-blocking tool.
Thank you.
Some features of ATS will be disabled while you continue to use an ad-blocker.
Google Video Link |
Originally posted by plube
the NIST report even says the fires did not get more than 600c in their own testing.
and the fires that appraoched 1000c was in a localized area which to me says it would not lead to global collapse.
In general, steel retains strength and stiffness approximately equal to 50 percent of its strength and stiffness at ambient conditions at a temperature of 1,100 °F (593 °C).This is comparable to the strength and stiffness reductions for ordinary concrete. At 1,300 °F (704 °C), steel retains about 20 percent strength and stiffness. A near-total depletion of strength occurs at approximately 2,200 °F (1,204 °C)...
It can be said with confidence that structural steel does not melt in building fires, although such possibility is theoretically possible for certain conditions (comparable to melting furnace conditions). Building fires simply do not generate steel melting temperatures that are around 2,700 °F
(1,500 °C).
but i will address your issues shortly....I must say you at least are one of the most sincere OSer's by presenting well with great information...and it is a pleasure to read through it.
reply to post by Drunkenparrot
Lastly we have...
An perfectly inelastic collision between equal mass in 1 dimension demonstrating both conservation of total momentum and kinetic energy associated with some energy loss.
Look familiar yet?
reply to post by Drunkenparrot
Next up, calcing out the stress redistribution from the P-Δ effect at the columns
Originally posted by Joey Canoli
reply to post by Drunkenparrot
Lastly we have...
An perfectly inelastic collision between equal mass in 1 dimension demonstrating both conservation of total momentum and kinetic energy associated with some energy loss.
Look familiar yet?
Oh noes.....
You're gonna totally confuse the poor darlings with this. They're gonna look at this and say, " look at the evidence you provided for us !! This proves that the collapse should have decelerrated !!! Nyah nyah nyah !! Eleventy !!!11!!111!!!
But of course, those of us that actually understand physics will recognize that gravity isn't represented in that gif, and will just be amused by truther responses.
Originally posted by plube
reply to post by Joey Canoli
For one thing....just because you show this Gif again thinking it somehow represents anything to do with the collapse of the towers shows your ignorance again....and you do not show a source for the gif.....shame.
but besides your trying to lie again which your calling us truthers out on shows who is the deceiving force here yet again does it not.
that is a perfect inelastic collision...LISTEN TO THIS....in a perfect world in a vacuum ....NO friction involved either.....you see the two grey squares i aassume that is a connection point being represented...where the ststem joins and continues in the same motion......hmmmmmmm.
yup sure does represent what we are discussing.....NOT
here lets simplify yet again shall we instead of baffling with BS......
Consider the inelastic collision between the two freight cars shown here. The momentum before and after the collision is the same. The KE, however, is less after the collision than before the collision. How much less, and what has become of this energy?
Remember that the two freight cars have the same mass, which we'll represent as m. The initial kinetic energy is that of the single freight car moving at v = 10 (no units are given, so we won't worry about units):
½ × m × 102 = 50m. (The momentum is 10m.)
After the collision, the momentum of the total system is the same 10m, but since the moving cars now mass 2m, the final velocity is 5. The kinetic energy is found using these values:
½ × 2m × 52 = 25m,
or only half the kinetic energy before the collision!!!
What has become of this energy? It has been "dissipated" by the shock of collision, for example in the jolt and rattling experienced by the cars.
source
Inelastic collision:- The collision in which kinetic energy of the system is not conserved but momentum conserves, then that collision is known as inelastic collision.
In the case of inelastic collision only momentum of the system is conserved and kinetic energy of the system is not conserved.
Ex: Collision of a bullet with a block of wood.
One dimensional elastic collision:-Before and after collision, if the velocities of the bodies involved in collision are along the same straight line, then such collisions are known as one dimensional collision.
Coefficient of restitution: It is defined as ratio of relative velocity of separation (v2-v1) after the collision to the relative velocity of approach (u1 –u2) before collision. It is represented by the symbol “e”.
source
As you can see....who is not able to understand what is being stated.....but is simpler terms than going to wiki-pedia and just grabbing a GIF.......and saying this is so.....these are examples of physics in the simplist of terms....NOT ONE of my examples or yours are taking friction of the real world into account.....they are to show conservation of momentum laws....but they are not showing the energy tranfers and the loss of energy during the collisons....
thanks for your failed analysis again Joey Canolli......why not start speaking truthfully instead of trying to lie to people in a thread where the truthers are the ones that are apparently being called out...the reason no one bothered to answer you on this question is because it was so easy to show how it completely and utterly fails.
The whole collapse senario in the towers is about the amount of energy required to bring down the towers...the energy require to cause complete global failure.....thank you for trying though Joey.....but you keep on stumbling over yourself with your own belief in the OS as complete truth.edit on 013030p://f33Thursday by plube because: (no reason given)
The only source of energy which is available to the falling mass is potential energy and unless that energy is released by collapse of further columns the falling mass will come to a halt.
Originally posted by waypastvne
I have corrected the sentence below.
The only source of energy which is available to the falling mass is potential energy and unless that energy can be transmitted into the columns by the strength of the truss seat connections the falling mass will continue.
Would you like me to check for more mistakes ?
Originally posted by ANOK
I fact it makes no sense at all.
Originally posted by plube
the truss seats would not transfer great energy
Originally posted by plube
that is a perfect inelastic collision...
Consider the inelastic collision between the two freight cars shown here. The momentum before and after the collision is the same. The KE, however, is less after the collision than before the collision. How much less, and what has become of this energy?
What has become of this energy? It has been "dissipated" by the shock of collision, for example in the jolt and rattling experienced by the cars.
As you can see....who is not able to understand what is being stated.....but is simpler terms than going to wiki-pedia and just grabbing a GIF.......and saying this is so.....these are examples of physics in the simplist of terms....NOT ONE of my examples or yours are taking friction of the real world into account.....they are to show conservation of momentum laws....but they are not showing the energy tranfers and the loss of energy during the collisons....
The whole collapse senario in the towers is about the amount of energy required to bring down the towers
Originally posted by plube
Object A the upper part of the tower...which has potential energy.....a floor is completely removed(According to Bazant) which is then accelerated by a force...Gravity....Object A now has Kinetic Energy....
now all three building have a different amount of Potenial energy
which means they all have variable amounts of Kinetic energy(i would go into more depth of the amounts but wont)
but most work done on the towers was done concerning South tower
WHY? simple...because The OS would have to try it to be proved to be the case that brought the towers down all the way to the bottom as it had the least amount of potential energy and if it could not be proved in the one with the least amount of Potential energy then i would be disastrous for the OS......well it is disastrous for the OS as they struggle to prove there was sufficient Kinetic energy to progress the collapse to the bottom.
So we do not need to turn these example onto the side as we know all the forces involved
we can get a fairly close approximation of the mass of the 16floors from the south tower so we know the Potential energy to a reasonable degree and we know what Bazant has stated and so we know with a fair degree of accuracy the Kinetic energy
but the thing that is more problematic is if there was enough kinetic energy to bring the building all the way down......Well It has been shown there was an energy deficit by Gordon Ross and others that there is not
you can read his paper here
Originally posted by ANOK
Do you know what pressure the floor connections could withstand before failure? Or the concrete, or steel pans?
Originally posted by plube
alsoe the truss seats would not transfer great energy as they are there to suppot the floors themselves not the structure
which is yet another reason why the destruction of the core columns and the exterior columns does not make sense