Moon buugy footage question

reply to post by Pilgrum

For the first 2 secs with a = 1.6 & u = 0: S=1/2.a.t^2 = 3.2m
On earth the same first 2 secs give an S of 19.6m

So six times slower than on earth as I stated..
Thanks..

reply to post by backinblack


So you'd see the problem with the earlier statement:

Note the 1.6m/s/s is acceleration, not velocity..
So you would expect an item on the moon would take 2 seconds to fall the first 1.6 meters...
Given it started with zero velocity...

2 seconds fall from standstill at 1/6 earth gravity results in a distance of 3.2m
1.6 metres at that gravity from standstill takes 1.41 seconds, not 2 but sqrt(2) in this case

yep I'm pedantic

reply to post by Pilgrum


lol, no problems mate..
I had it right at 0.8 meters in one sec and then forgot it was still accelerating..
You didn't mess up what I was saying at all..
It's still 1/6 the speed as on earth which was the point..

But I don't mind admiting when I make a mistake unlike some..