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When considering atmospheric or oceanic dynamics, the vertical velocity is small and the vertical component of the Coriolis acceleration is small compared to gravity. For such cases, only the horizontal (East and North) components matter. The restriction of the above to the horizontal plane is (setting vu=0): \boldsymbol[ v] = \begin[pmatrix] v_e \\ v_n\end[pmatrix]\ , \boldsymbol[ a]_c = \begin[pmatrix] v_n \\ -v_e\end[pmatrix]\ f\ , where f = 2 \omega \sin \varphi \, is called the Coriolis parameter. By setting vn = 0, it can be seen immediately that (for positive \varphi and \omega\,) a movement due east results in an acceleration due south. Similarly, setting ve = 0, it is seen that a movement due north results in an acceleration due east. In general, observed horizontally, looking along the direction of the movement causing the acceleration, the acceleration always is turned 90° to the right and of the same size regardless of the horizontal orientation. That is...
Originally posted by astronomine
I apologize, as I don't know if this issue has been covered already, but why did the Russians first deny responsibility then reclaim it?
Originally posted by astronomine
I apologize, as I don't know if this issue has been covered already, but why did the Russians first deny responsibility then reclaim it?
Originally posted by dirtydog
Oh by the way the fire coming out the ass end of a rocket doesn't stop after 1st stage or stop at all before reaching its intended height. So to the debunkers who say its a missle were the hell is the flame from said missle.
[edit on 12/14/2009 by dirtydog]
But I'm sure Phage will be along any moment now to tell your wrong because:
A) Your angles aren't oblique enough
B) Your otherwise just wrong because hes always right
*link to CNN article which is vague at best*
And his post will be starred 1200 times
Originally posted by astronomine
I apologize, as I don't know if this issue has been covered already, but why did the Russians first deny responsibility then reclaim it?
a normal full moon has an angular value of approx 0.5 degrees
Originally posted by djusdjus
also, there is the assumption that the sub is launching from where the poster says it's launching.