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The square of the energy of sound is the energy of a sound wave, which is a wave of pressure that travels through a medium.
The total energy of a system can be used to understand how the system behaves and to predict how the system will change over time.
originally posted by: IAMUnification
Does this help at all?
E_binding = ((E_light*E_sound) + (E_sound*E_light) - (E_sound*E_light^2)*(E_light*E_sound^2))E_light^2
BE = (Zmp + Nmn - MA)c^2
Where:
BE is the binding energy is E_binding
Z is the number of protons is E_light
mp is the mass of a proton is E_sound
N is the number of neutrons is E_sound
mn is the mass of a neutron is E_light
MA is the mass of the nucleus is (E_sound*E_light^2)*(E_light*E_sound^2)
c is the speed of light is E_light^2
Follow-Up #2: sound vs. light
Q: It is true that sound and light are alike only to the extent that they are both waves. They are inherently different on the basis that light is electromagnetic radiation. It requires no medium and can therefore can propagate through both extremely sparse - space, upper atmosphere - and extremely dense - plastics, water - environments. Sound however, requires sufficient medium. It is required to have the interaction of molecules of the medium with other molecules of the medium. This is why, upon interrupting the medium with dense objects like foam, the interaction of molecules on one side of the interrupter can not transfer to those on the other side of the interrupter and can even be absorbed by the interrupter. One might say that light can be blocked as well, and they would be right. A leaf of an oak tree does absorb light and reflect light. Forests are darker than standing on a rooftop on a cloudless day. But the propagation of sound being in a medium of air, means that it relies on its own medium to transmit its propagation to somewhere else. Because light does not have a medium, it can transmit through objects in a way that sound cannot. SOUND REQUIRES MEDIUM.
- Wilson (age 19)
Charlotte, NC
A: What you say is true.
Follow-Up #3: hearing Tesla resonators
Q: Okay, so we know sound requires a medium and light does not. Forget that for a moment and consider the following: Tesla resonators for example. It emits electromagnetic energy of its resonant frequency usually in the high RF spectrum. What if the resonant frequency was, say, 500Hz. Would you HEAR it when it resonates? What if the resonant frequency was 4*10^6Hz? Would it emit color since after all light is electromagnetic energy and the resonator is emitting that EM energy at a visible frequency?
- Harrison (age 22)
Bloomfield, MI, US
A: If I understand right, a Tesla resonator is a type of electromagnetic waveguide. Although you would not directly hear the electromagnetic wave, you might hear some ordinary sound waves created by stresses and strains in the resonator as the EM wave traveled through it. If the EM wave was at 500 Hz, the lowest frequency sound would be at 1000 Hz, since the stress from the EM fields is the same if you flip their direction. To get 500 Hz sound out you'd need to drive some sort of element other than the Tesla resonator. Any sort of loudspeaker would do.
4*106 Hz is far below the visible frequency range. If you do make a waveguide for visible light, say with fiber optics, you can of course see the light that comes out. I don't see a good way to make that sort of waveguide with Tesla resonator, especially when there are such better alternatives.
Source