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originally posted by: pfishy
originally posted by: ImaFungi
a reply to: pfishy
When a bowling ball is dropped off the top of a skyscraper;
According to modern physics best understanding of reality, and the aspect of reality we term 'gravity';
What physically is forcing the ball to move?
Does EM radiation (which from now on for convenience sake I will refer to as; light) 'created' 'in/as' the sun move as particles from the location of the suns body, to the location of the earths body? As if the sun was 'throwing baseballs towards earth', as an analogy, to the sun 'throwing light towards earth'?
Ok, I have to admit that the phrasing of the second part of your question is a bit confusing, but let's go ahead and see where we can get with this. I'll give you my answer, then you give me yours and we can see if they differ.
The bowling ball is acting on potential energy, due to the gravitational field of the Earth exerting a constant pull on it. The forces acting upon it are momentum energy and gravity. Now, I suspect that this answer won't satisfy you, so you can elaborate on your question in your response.
Photons are emitting by excited electrons moving between energy states. The direction in which any given photon moves is determined by the local charge field of the electron. So, as they are generated in the Sun's core, and spend around 10,000 years bouncing off protons and such, they work their way to the surface and travel in whatever direction the ended up leaving the core in. Until they are absorbed or reflected. But no, they are not baseballs. Baseballs are mostly composed of baryonic matter. Photons are not. They are most likely massless. (Current experiments have set an upper limit for the mass of a photon, but have not shown them to have mass. We just know that if they do, it is less than the limits of that our equipment can detect. And it would be so small as to be negligible in pretty much every significant way.)
Ok, I know that you are actually asking about the nature of the photon itself, as well as its creation and direction of travel. Photons are quanta of energy. They have properties of both particles and waves. They travel and act like a wave until interactions with matter collapse their waveform and they isolate as a single particle. When they are emitting by electrons, they are moving a relativistic speed. Slightly less than 300,000 km/sec. Passing through matter can slow this speed, but it resumes full speed in a vacuum. As for the reason behind the constant speed in a vacuum, even after being slowed by matter, I do not have a solid explanation. I'm not a physicist.
But the collapse from wave to particle is evident in the fact that an electron can absorb a photon. Electrons are many times smaller than any wavelength of light. This is why we use electron microscopy. Electrons can provide a resolution that light cannot. But if light were purely waves, the photon would only lose a small amount of energy when it encountered an electron. Much like a wave at the shore of the ocean does not cease to exist because part of it hits the piles supporting a pier, or a person standing in the water.
You were doing OK until you said "energy goes in the atom and it releases it again", since it's pretty easy to show that can't be what happens because atoms have discrete energy states and we don't see this discrete behavior in the transmission of light through glass. It's actually absorbed by the lattice structure, and re-emitted from that, not from individual atoms:
originally posted by: dragonridr
To answer your question light always moves at C. When we say it slows down in a medium well what we should say is ot takes more time. What happens in say glass when a photon hits the glass it is absorbed than re transmitted. This continues until it exits the final photon that exits the glass is not the same one that entered. This same thing happens in a mirror light is absorbed and it is transmitted. Basically energy goes in the atom ans it releases it again trying to get back to its ground state.
A common explanation that has been provided is that a photon moving through the material still moves at the speed of c, but when it encounters the atom of the material, it is absorbed by the atom via an atomic transition. After a very slight delay, a photon is then re-emitted. This explanation is incorrect and inconsistent with empirical observations. If this is what actually occurs, then the absorption spectrum will be discrete because atoms have only discrete energy states. Yet, in glass for example, we see almost the whole visible spectrum being transmitted with no discrete disruption in the measured speed. In fact, the index of refraction (which reflects the speed of light through that medium) varies continuously, rather than abruptly, with the frequency of light.
Secondly, if that assertion is true, then the index of refraction would ONLY depend on the type of atom in the material, and nothing else, since the atom is responsible for the absorption of the photon. Again, if this is true, then we see a problem when we apply this to carbon, let's say. The index of refraction of graphite and diamond are different from each other. Yet, both are made up of carbon atoms. In fact, if we look at graphite alone, the index of refraction is different along different crystal directions. Obviously, materials with identical atoms can have different index of refraction. So it points to the evidence that it may have nothing to do with an "atomic transition".
When atoms and molecules form a solid, they start to lose most of their individual identity and form a "collective behavior" with other atoms. It is as the result of this collective behavior that one obtains a metal, insulator, semiconductor, etc. Almost all of the properties of solids that we are familiar with are the results of the collective properties of the solid as a whole, not the properties of the individual atoms. The same applies to how a photon moves through a solid.
A solid has a network of ions and electrons fixed in a "lattice". Think of this as a network of balls connected to each other by springs. Because of this, they have what is known as "collective vibrational modes", often called phonons. These are quanta of lattice vibrations, similar to photons being the quanta of EM radiation. It is these vibrational modes that can absorb a photon. So when a photon encounters a solid, and it can interact with an available phonon mode (i.e. something similar to a resonance condition), this photon can be absorbed by the solid and then converted to heat (it is the energy of these vibrations or phonons that we commonly refer to as heat). The solid is then opaque to this particular photon (i.e. at that frequency). Now, unlike the atomic orbitals, the phonon spectrum can be broad and continuous over a large frequency range. That is why all materials have a "bandwidth" of transmission or absorption. The width here depends on how wide the phonon spectrum is.
On the other hand, if a photon has an energy beyond the phonon spectrum, then while it can still cause a disturbance of the lattice ions, the solid cannot sustain this vibration, because the phonon mode isn't available. This is similar to trying to oscillate something at a different frequency than the resonance frequency. So the lattice does not absorb this photon and it is re-emitted but with a very slight delay. This, naively, is the origin of the apparent slowdown of the light speed in the material. The emitted photon may encounter other lattice ions as it makes its way through the material and this accumulate the delay.
Moral of the story: the properties of a solid that we are familiar with have more to do with the "collective" behavior of a large number of atoms interacting with each other. In most cases, these do not reflect the properties of the individual, isolated atoms.
You probably did, but it may have been wrong too. This idea about an atom in glass absorbing and re-emitting photons is a popular misconception. It's interesting how the behavior of large groups of atoms can differ from the behavior of individual atoms.
originally posted by: pfishy
Now that you mention it, I do believe that I have read that before. Thanks for the info.
Like I said, I don't know much about gravitons, because not only are they only hypothetical, but we know that there are problems trying to treat virtual gravitons the way we might treat virtual photons. So, I'm afraid until we have a workable theory of quantum gravity, or some alternate theory along those lines, we don't have good answers to this question.
originally posted by: ImaFungi
In what you know of graviton theory; We drop a bowling ball off of a skyscraper, according to what you know, is it proposed that, the bowling ball falls, because graviton particles push and/or pull it down?
You don't have to accept that gravity is a "force" in order to believe that gravitons might exist. According to QM, anything that behaves like a harmonic oscillator has discrete energy levels, as I said in part 1. General relativity allows gravitational waves, ripples in the geometry of spacetime which travel at the speed of light. Under a certain definition of gravitational energy (a tricky subject), the wave can be said to carry energy. If QM is ever successfully applied to GR, it seems sensible to expect that these oscillations will also possess discrete "gravitational energies," corresponding to different numbers of gravitons.
Quantum gravity is not yet a complete, established theory, so gravitons are still speculative. It is also unlikely that individual gravitons will be detected any time in the near future.
Furthermore, it is not at all clear that it will be useful to think of gravitational "forces," such as the one that sticks you to the earth's surface, as mediated by virtual gravitons. The notion of virtual particles mediating static forces comes from perturbation theory, and if there is one thing we know about quantum gravity, it's that the usual way of doing perturbation theory doesn't work.
Quantum field theory is plagued with infinities, which show up in diagrams in which virtual particles go in closed loops. Normally these infinities can be gotten rid of by "renormalization," in which infinite "counterterms" cancel the infinite parts of the diagrams, leaving finite results for experimentally observable quantities. Renormalization works for QED and the other field theories used to describe particle interactions, but it fails when applied to gravity. Graviton loops generate an infinite family of counterterms. The theory ends up with an infinite number of free parameters, and it's no theory at all. Other approaches to quantum gravity are needed, and they might not describe static fields with virtual gravitons.
originally posted by: Phantom423
a reply to: ImaFungi
Doesn't general relativity answer your question? Gravity is space-time warp which is described by classical mechanics (we don't have a quantum theory).
In your example above, you say that the planet is at rest with no other mass or force around it. But yet you say it's moving. What's moving it?
The intrigue for me is in trying to understand exactly why the presence of mass has the gravitational effect it does. But once we accept that it does (for reasons we can't fully explain, hence why we call gravitation a "fundamental" interaction), the math of relativity defines the expected gravitational effects of the scenarios you describe.
originally posted by: ImaFungi
Cant you see the intrigue there?
originally posted by: dragonridr
a reply to: Arbitrageur
Much easier to explain it that way than I don't have to explain the electron lattice. Basically with refraction you can see the charge travel though glass. Or in certain experiments stop it But bottom line it's still atoms absorbing and releasing energy. So Your Kind Of Being Picky.
originally posted by: dragonridr
With this you also learn about monopoles everything in the universe is controlled by spin. Including why matter can't occupy the same space. Every question you ask involves spin. Once you realize electrons spin all the time it should start to make sense. They don't vibrate like I've seen you say.
The spin creates a magnetic field In a magnet or a copper wire.
We've sent the Voyager spacecraft off into space, and other probes also. As the link I posted calculated, it takes a velocity of 11,181 m/s or greater to escape Earth's gravity. So any velocity less than that would keep the ball from continuing away from Earth forever, since it wouldn't have the necessary velocity to escape Earths gravity.
originally posted by: ImaFungi
a reply to: Arbitrageur
Try to answer my questions about throwing the baseball from the square mark off the back of the earth without movement, what physically would keep the ball from continuing off into space?
Bubbles have defined edges The gravitational well diagram I posted has no defined edge. I'm sorry you can't see why bubbles aren't a very accurate representation, but it should be obvious from studying the well diagram and seeing the difficulty of drawing a bubble which shows the same thing. I don't know how you could do it.
I only used bubble, because I like to get to as close to truth as possible, and a 3 dimensional well around an object might be something of a bubble.
I keep seeing string theorists say they are going to figure out ways to experimentally test string theory, but I'm not seeing the experiments proving it. Maybe with the LHC upgrade we will see some results that give us some clues one way or another, but they are saying it will really take until 2016 at the earliest to get enough statistics analyzed in the latest experiments there.
originally posted by: andy06shake
a reply to: Arbitrageur
What about the implied extra dimensions that string theory suggests, do they actually exist?
originally posted by: Phantom423
a reply to: ImaFungi
I understand - I just picked up on that one scenario where the object is at rest with no mass or applied force.
So if the object is at rest, the object is an inertial reference frame with no reference i.e. no outside force or reference to act on it. So F = ma where F and a are usually vector quantities, and F = mg where g is acceleration due to gravity are meaningless. So gravity has to = 0. It takes two to tango to have gravity - can't think of any other scenario for an isolated object in an adiabatic system with 0 references. Even if there was an isolated photon which has no mass, there would be some interaction to induce some small gravitational effect (I think). But in a world consisting of a single object, I think gravity has to = 0.
originally posted by: Arbitrageur
We've sent the Voyager spacecraft off into space, and other probes also. As the link I posted calculated, it takes a velocity of 11,181 m/s or greater to escape Earth's gravity. So any velocity less than that would keep the ball from continuing away from Earth forever, since it wouldn't have the necessary velocity to escape Earths gravity.