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originally posted by: Nochzwei
Interesting concept, may work.
Some engineering hurdles will be there to actually get a large space craft with this drive built into it.
a reply to: tachyonator7
originally posted by: tachyonator7
true, in basic design, it would need two engines stretching and releasing two pairs of strings periodically. smallers the intervals between firing of the strings, smoother would be the acceleration.
originally posted by: boncho
A spring exerts the same amount of force on either end, please tell us when a person can push themselves with a human hair in space, how equal and opposing force is going to move anything anywhere?
originally posted by: jonnywhiteI think the OP is suffering from the same thing many of us here suffer from. There's a tendency to have an overinflated sense of understanding when you just start to scratch at the surface of something...
originally posted by: tachyonator7
funny your location is "corporate shillquarters". read the thread, you missed all the key points. when one side of the spring is released, there is only one force at work, contracting it towards the opposite end, smashing it to the inner wall of the tube and transfering that kinetic energy to the tube making it move. it's has nothing to do with human hair, it's a simple transfer of inertia.
originally posted by: boncho
A spring exerts the same amount of force on either end, please tell us when a person can push themselves with a human hair in space, how equal and opposing force is going to move anything anywhere?
believe I said earlier you are ignoring the entire system and only taking into consideration what you want to.
Answer this... How do you load the springs?
originally posted by: tachyonator7
believe I said earlier you are ignoring the entire system and only taking into consideration what you want to.
Answer this... How do you load the springs?
i'm not ignoring anything, you are. it is irrelevant how spring is loaded, manually or by a motor. the point is when fired, it makes the tube blast off like a bullet. this is the law of physics, law of nature.
originally posted by: tachyonator7
you clearly lack any understanding of basic laws of physics and you don't know what you are rambling about. i explained why you are totally wrong, but you persist in your delusion. let me quote you:
originally posted by: tachyonator7
originally posted by: WeAre0ne when your device is on the ground, and you release the bottom side of the spring, the top side of the spring is being held by the top of the outer tube, which is pushing down the sides of the tube, down on the ground.
nothing is pushing down on the ground, if that was the case, placed on the scale, tube would increase in weight before it jumps, which is not the case.
originally posted by: tachyonator7
there is NO force 1 and force 2, two opposing forces exist only when both ends are released at the same time.
there is just a elastic-potential energy in the spring taut between two hooks. when ONE of the sides is released the elastic-potential energy in the spring will act as a force in a given direction, contracting towards the opposite end and tranfering it's kinetic energy to the tube, makeing it move.
originally posted by: tachyonator7
so, both your claims are wrong. to summerize:
1. tube doesn't get heavier before it jumps
2. when bottom of the spring is released, there is only one unidirectional force
originally posted by: bonchoHere's a good point. So it's like a bullet right? Is it something like this?
By the by... Springs in space:
originally posted by: boncho
We should really address the thing that started it all though, the idea you have about moving the boat by leaning forward:
If everything were frictionless, or in an environment like space, you couldn't move the boat at all. It's just that there is some friction with the boat against the water, and it makes it able for you to inch it forward a bit. (If it even did or you just perceived as such).
It's kinda like if you take a rug, or fowl you can move your body in a way to push it forward. Not really a good space propulsion system though....
Riiiiiight. Suuuuure.
The entire weight of the tube and spring is pushing down on the ground... that is all I was talking about....
I didn't say anything about increasing weight before it jumps, because the mass of the entire object doesn't change. You clearly misunderstood what I was trying to say, in layman's terms none-the-less.
Again...
When your device is on the ground, and you release the bottom of the spring, the spring tries to contract inwards towards its center. The bottom half is contracting upwards, and the top half is trying to contract downwards. However the top part of the spring can't move downwards because it is fixed in place by the top and sides of the tube, which are held up in place by the ground.
Completely wrong.
A spring always tries to contract towards its center. There are two forces. Force 1 (green arrow) and Force 2 (blue arrow). The only reason the center point (red line) of the spring moves to the right is because force 2 (blue arrow) is contracting inwards, and because the right side is fixed in place. If the right side of the spring wasn't fixed in place, the red line would not move. If force 2 didn't exist, only half the spring would contract (force 1) and the red line would not move. Some springs are even designed to have a greater force 1 (green arrow) and lesser force 2 (blue arrow). Did you know that?
The hooks on each side of the spring want to reach the center of the spring (red line). If the above device was in zero gravity, in a vacuum, and you released the left hook; Both the left hook and right hook will try to reach the center of the spring (much like releasing both sides at the same time).
Force 1 (green arrow) will be combined with the weight of the spring to form kinetic energy in one direction, and force 2 (blue arrow) is combined with the weight of the tube to form kinetic energy in the opposite direction. They both cancel each other out.
1: I never claimed it got heavier. The mass of the tube and spring doesn't change.
2: Simply no.
you show it with your claims.
Mass on a Spring
Consider a compact mass m that slides over a frictionless horizontal surface. Suppose that the mass is attached to one end of a light horizontal spring whose other end is anchored in an immovable wall. (See Figure 1.) At time be the extension of the spring: that is, the difference between the spring's actual length and its unstretched length. can also be used as a coordinate to determine the instantaneous horizontal displacement of the mass.
The equilibrium state of the system corresponds to the situation in which the mass is at rest, and the spring is unextended (). In this state, zero horizontal force acts on the mass, and so there is no reason for it to start to move. However, if the system is perturbed from its equilibrium state (i.e., if the mass is displaced sideways, such that the spring becomes extended) then the mass experiences a horizontal force given by Hooke's law,
Newton's second law of motion leads to the following time evolution equation for the system , where
This differential equation is known as the simple harmonic oscillator equation, and its solution has been known for centuries.
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As we have seen, when a mass on a spring is disturbed it executes simple harmonic oscillation about its equilibrium position. In physical terms, if the mass's initial displacement is positive ( x > 0 ) then the restoring force is negative, and pulls the mass toward the equilibrium point ( x = 0 ) However, when the mass reaches this point it is moving, and its inertia thus carries it onward, so that it acquires a negative displacement ( x < 0 ) The restoring force then becomes positive, and pulls the mass toward the equilibrium point. However, inertia again carries it past this point, and the mass acquires a positive displacement. The motion subsequently repeats itself ad infinitum. The angular frequency of the oscillation is determined by the spring constant, k , and the system inertia, m.
sorry "hub", but it does.
springs contract toward the opposite end, not the center. what do you imagine force 2 is acting against?