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The Army's 8-Wheeled Laser Truck Can Burn Mortars, Drones Right Out Of The Sky By Amanda Macias, Business Insider, December 12, 2013
For the first time, the U.S. Army Space and Missile Defence Command used a vehicle mounted high-energy laser to successfully engage more than 90 enemy mortar rounds and flying unmanned aerial vehicles (UAVs). The High Energy Laser Mobile Demonstrator (HEL MD) contracted by Boeing, was tested at White Sands Missile Range and confirms the capability of a mobile laser weapon system to counter rockets, artillery, mortars, UAVs, and reconnaissance sensors mounted on UAVs.
The beam control system (BCS) is a dome-shaped turret that extends above the roof of a 500-horsepower Heavy Expanded Mobility Tactical Truck (HEMTT). The beam director rotates 360-degrees and uses mirrors to point and focus the beam on a target.
"These tests were the first in which HEL MD repeatedly destroyed consecutive rounds of mortars and aerial threats with speed-of-light precision and a high degree of accuracy," Mike Rinn, vice president, Boeing Directed Energy Systems. The recent testing utilized a 10 kW class laser which will be upgraded to an 100 kW class laser in subsequent demonstrations.
Wrabbit2000
Stupid question...but one that came right to mind. What is the range on these things? Specifically...if they miss ... does the laser energy dissipate and disperse into the atmosphere or is that loud screech someone gets on their satellite call the sound of the miss connecting with a comm-satellite which just happened to pass through the line of fire, downrange?
That's a totally ridiculous comparison. It's like comparing a 155mm Artillery Piece to a BB gun
Wrabbit2000
reply to post by sirhumperdink
A pen laser? That's a totally ridiculous comparison. It's like comparing a 155mm Artillery Piece to a BB gun. Two RADICALLY different levels of power and impact with, I'm sure, two VERY different levels of potential harm to overshoots.
Now, a man can stand here on Earth and bounce a laser off the reflectors on the moon. You don't have to be NASA and you don't need billion dollar equipment to do that. You also don't need a 100kw Laser as this mentioned as being part of the future packages. A little goes quite a way with a laser.
To give an idea of the level of comparison here..one of the most powerful consumer lasers in the world today is the Spyder 3 (AKA The Lightsaber, as coined in the press) and it's related products, found Here. It's $300 and set records not that long ago when it first hit the market. It first released with 1 Watt effective power. As you can see, what is there now is up to 2 Watts.
What they fired for this story was 10,000 watts and what they intend to have the production model mounting, according to the story, is 100,000 watts. So..I do think a question about range is relevant, as it so happens.edit on 13-12-2013 by Wrabbit2000 because: (no reason given)
The Laser Ranging Retroreflector experiment was deployed on Apollo 11, 14, and 15. It consists of a series of corner-cube reflectors, which are a special type of mirror with the property of always reflecting an incoming light beam back in the direction it came from. A similar device was also included on the Soviet Union's Lunakhod 2 spacecraft. These reflectors can be illuminated by laser beams aimed through large telescopes on Earth. The reflected laser beam is also observed with the telescope, providing a measurement of the round-trip distance between Earth and the Moon.
Source
Laser beams are used because they remain tightly focused for large distances. Nevertheless, there is enough dispersion of the beam that it is about 7 kilometers in diameter when it reaches the Moon and 20 kilometers in diameter when it returns to Earth.
Wrabbit2000
reply to post by sirhumperdink
As a matter of fact, you can calculate it, and I have, while I was off checking some things about how people currently bounce lasers off those lunar reflectors left by the Apollo Missions.
It's interesting to see...and confirms what I was worried about. This most definitely CAN tag something higher ...although I wonder if they'll mention that or if the capability will be on it's 'Classified' spec sheet? Anyway.. I have a college math final late this afternoon, so this was something to get in the mood.. kinda.. lol
Anyway, first the reference for it to make sense on the OP story and OP test unit.
The Laser Ranging Retroreflector experiment was deployed on Apollo 11, 14, and 15. It consists of a series of corner-cube reflectors, which are a special type of mirror with the property of always reflecting an incoming light beam back in the direction it came from. A similar device was also included on the Soviet Union's Lunakhod 2 spacecraft. These reflectors can be illuminated by laser beams aimed through large telescopes on Earth. The reflected laser beam is also observed with the telescope, providing a measurement of the round-trip distance between Earth and the Moon.
and..
Source
Laser beams are used because they remain tightly focused for large distances. Nevertheless, there is enough dispersion of the beam that it is about 7 kilometers in diameter when it reaches the Moon and 20 kilometers in diameter when it returns to Earth.
Now, average distance to the moon is 382,000 Kilometers. It varies by nearly 45,000 kilometers, so the average will have to do. 7 Kilometers at the surface makes for about 55,000 Kilometers distant for every Kilometer in diameter. Geosync Orbit is 36,000 Kilometers, so you're not quite a full Km in diameter to light up something at that altitude.
On the other hand.... ISS is orbiting at a tree skimming altitude (by comparison) of 370 Kilometers. So... if 55,000 km is a km wide ...26,500 would be a half kilometer...13,250 would be a 1/4 of a kilometer... (sounds of pencil scribbling and number punching)
If the numbers for lasing the Apollo reflector targets on the moon are accurate, and you turned that toward the ISS as an example, you'd hit the Station with a source laser of 100,000 watts at roughly 22 feet in diameter. (If I didn't make some big boo boo somewhere, anyway)
Wrabbit2000
reply to post by sirhumperdink
How do you figure I am missing anything? The ACTUAL measured beam as currently being fired by much weaker, non-destructive lasers is 7 kilometers across on the moon's surface. Everything else was just working numbers backwards for scale.
The point is, there isn't anything to account for when I'm starting with a known and measured constant that is already being measured from passing through the same atmosphere you're talking about.
We're also talking about civilian lasers for survey and distance measurements, not military/weapons grade with power orders of magnitude beyond what is being used in a telescope. That is something I did not account for because it would have skewed the numbers to a more destructive beam at low altitude, not less so.
It's very reasonable to presume that a Military weapons system, designed for the purpose, will have tighter tolerances and control than a scientific laser where they really don't care about the diameter, but simply the measurement of time in transit.
** To be honest, I was asking a serious question on this thread. I know we have ATS members who can rattle off what it took me effort to look up and calculate without having to go through that. I was hoping for a reply from one of our science based folk..tho now that I've done the work anyway, I guess it's not as important now.
Wrabbit2000
reply to post by sirhumperdink
Well, I'll put it this way, because I'm not going to debate your opinion. If you can give a little support in how what your explaining works to differ, I'll be happy to look at it. It really does sound interesting....and again, I asked what I did here for a SERIOUS REPLY...not for an endless debate to everything said, and every reply made.
I'm interested in that as a weapons system I would like to estimate capability for...in a serious effort. Hence, the request for research based data on your points ..which I would find useful today ...vs. opinion, which, at the moment, is about the last thing I'd been seeking.
Sorry for that misunderstanding... I'm not accustomed to this forum necessarily being an aggressive debate one. I should have noted that it wasn't the goal.
Wrabbit2000
To give an idea of the level of comparison here..one of the most powerful consumer lasers in the world today is the Spyder 3 (AKA The Lightsaber, as coined in the press) and it's related products, found Here. It's $300 and set records not that long ago when it first hit the market. It first released with 1 Watt effective power.
crazyeddie68
You know...I think the gov't has a LOT of Tesla's inventions and ideas a reality today.I also believe that they have a type of "free energy" that they don't want to release.That would put every big oil and energy company out of business.Can't control the masses that way.