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Originally posted by OccamAssassin
This is where having a background in electrical engineering would help you all. Otherwise it's your Achilles heal.
Having a background in Mechanical Engineering would help you understand what is happening at the gear-box.
You would instantly understand why you have hit the academic brick wall when you approach universities.
I wouldn't recommend using a gearbox. I recommend timing V-belts. I also suggest you ask for clarification, in any area you do not understand, before you make assumptions off of the top of your head.
Originally posted by OccamAssassin
reply to post by bradagilah
I wouldn't recommend using a gearbox. I recommend timing V-belts. I also suggest you ask for clarification, in any area you do not understand, before you make assumptions off of the top of your head.
V-belts are actually much worse than coarse cut gears for loss, but that is beside the point.
I find it pretty funny that you keep ascertaining that you have a working(some of your posts seems to indicate that you have multiple units) unit and yet you seem to fail to have any videos (let alone a diagram) of any working units.
You fail to understand simple principles that any first year engineering student would be expected to know backwards and sideways. Simple principles such as torque and work seem to elude your theory yet you carry on that it is because someone else fails to understand electrical/magnetic theory rather than your own knowledge that is flawed.
The flaw in your theory isn't in the electrical principles.......It is in the mechanical aspects.
Think of RPM and torque in the same way as voltage and current.
If you double one....you halve the other ......and lose a little.
Invert the voltage by a factor of two and you divide the current by a factor of two.
Increase the rpm by a factor of two and you divide the torque by a factor of two.
Changing the ratio of rotation will cause losses. No matter how you do it.
Take into account, loss from friction, heat, sound and you are already running at a loss.
Also take in to account that the motor will never work at 100% efficiency. The input will ALWAYS be greater than the output!
Even if the system was perfect up to the generator, the generator is going to lose energy through friction and electro-magnetic losses. It is unavoidable.
As to the pole aspects of the motor.
One pole on a 24 pole 1 kW motor is 1/12th the power of the pole of a 2 pole 1 kW motor - all other things being the same.
What do you need to be convinced OccamAssassin?
Increase the rpm by a factor of two and you divide the torque by a factor of two.
There are no flaws what so ever in what I had to say, in regards to the mechanics or electronics. The flaws you seem to see, are as a result of your tunneled vision. And timing belts can have efficiencies of 98%, so losses, are not a problem...
Originally posted by OccamAssassin
reply to post by bradagilah
What do you need to be convinced OccamAssassin?
How about reading my previous post and then contemplate on the statement.....
Increase the rpm by a factor of two and you divide the torque by a factor of two.
Why did I say that?
There are no flaws what so ever in what I had to say, in regards to the mechanics or electronics. The flaws you seem to see, are as a result of your tunneled vision. And timing belts can have efficiencies of 98%, so losses, are not a problem...
Lets see, based on your own figures
The motor has an efficiency of between 95% - 99%
The timing belt setup has an efficiency of 98%(I doubt this very much and think you have pulled this figure out of your ar$e - I would typically expect to see efficiencies of around 99.8% with a timing belt and about 99.998% for coarse cut gears.
Just say well give you the benefit of the doubt and well go with the generous side of things
If we put 5kW into the motor
we end up with @99% efficiency 4950W at the shaft
after we go through the timing belt type ratio converter @98%
we end up with 4851W.
Now, can you tell me how you intend on turning 4851W into 5000W and make the motor keep turning?
Originally posted by bradagilah
Ok. Thanks for opening up to dialog. Let me break down what your saying, starting with putting 5 kW into the motor. The motor in question (Baldor EM3710T) requires 576 kW per hp. With the 5 kW being fed into that motor, the motor is theoretically capable of 8.6 hp. The generator head requires 6.7 hp to produce that 5 kW. As such, we have 1.9 hp of excess energy, ready to do something. That energy can be spent on compensating for any losses and can be used to power a load.
I'll clarify it further if that didn't make any sense... Let me know.
Originally posted by bradagilah
Ok. Thanks for opening up to dialog. Let me break down what your saying, starting with putting 5 kW into the motor. The motor in question (Baldor EM3710T) requires 576 kW per hp. With the 5 kW being fed into that motor, the motor is theoretically capable of 8.6 hp. The generator head requires 6.7 hp to produce that 5 kW. As such, we have 1.9 hp of excess energy, ready to do something. That energy can be spent on compensating for any losses and can be used to power a load.
Originally posted by Druscilla
Please, if you know so much, give us a solid working model of just ONE of these wonderful machines that exist in this magical fairy land you occupy where wizards break the laws of thermodynamics with every sip of coffee while they ride their unicorns that have amazing free energy tesla saddles.
All we want is ONE working model, no excuses.