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Originally posted by tgidkp
I would be very curious to hear anyone's (clprime?) explanation of the negative result.
Originally posted by CLPrime
reply to post by LilDudeissocool
Alrighty:
E^2 = (mc^2)^2 + (pc)^2
m is rest mass and p is momentum.
For an object at rest (p = 0), the right side of the equation disappears, and it becomes
E^2 = (mc^2)^2
That proves motion is time huh?
Originally posted by CLPrime
which, simplified, is
E = mc^2
So, E = mc^2 only applies to an object that's not moving. That is, it's the non-kinetic half.
Originally posted by CLPrime
If, on the other hand, the object has no rest mass (like a photon), that means m = 0 and the left side of the equation disappears, leaving
E^2 = (pc)^2
which, simplified, is
E = pc
So, E = pc only applies to a massless moving object. That is, it's the massless kinetic half.
This is what predicts that photons have momentum and, therefore, the ability to exert pressure.
When a massive object is moving, the entire equation applies.
edit on 18-11-2011 by CLPrime because: (no reason given)