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Originally posted by misterbeefy
Originally posted by misterbeefy
Originally posted by Shirak
Good job. You can increase the voltage by connecting more that one of these in SERIES with each other. You can retain the additional current by connecting some more in PARALLEL to the ones you already have in SERIES. Example:
2 circuits in series produces 14v .1 amp
Create 2 more of these and connect them in series as well for identical results. Now you have 2 circuits producing the said 14v .1 amp EACH.
Now connect the 2 "combined" circuits in parallel. This will give you the same voltage (14v) but DOUBLE your current. Now you have 14v and .2 amp, from a total of 4 of these circuits.
Try it with a total of 6 connected in a 3x3 configuration and you would have 21v and .3amp or 300 mA.
Keep in mind that each circuit would need the same antenna length/diameter, etc.
Another thing to consider is that your typical 12v car battery needs about 15.7 volts being fed to it to be able to charge. You could add some resistors to the circuit in parallel as well to balance out your voltage, while increasing the current.
Hope this helps.
ha ha, he's not going to get more voltage by doubling the circuits.....this isn't the same as a car battery where car batteries have a certain amount STORED in them, this thing is only able to get what it gets out of the air period....
And why wouldn't he? If he built IDENTICAL circuits, placing the antennas side by side, pointing in the same direction, made of the same materieals, etc., then he should obtain the same amount of radiant energy in circuit 2 as he would in circuit 1, thus doubling the voltage. The radiant energy isn't going to suffer a voltage drop just because he has one circuit tuned into it. Listen to your own statement, a car battery has a CERTAIN AMOUNT stored in them, radiant energy doesn't.edit on 17-8-2011 by misterbeefy because: (no reason given)
Originally posted by Shirak
reply to post by Pilgrum
Have you created this circuit yet? Any photos or component list?
I am looking to create a broader spectrum radiant energy meter this circuit looks like it could do the trick.
Originally posted by Alxandro
I think circuit that includes a resistor should be omitted from this discussion regarding radiant energy because of the fact that energy that is lost whenever you have resistance in the picture.
Resitors are meant to impede current flow, which in turn dissipates heat, which is essentially lost energy.
Having a resisitor in the circuit is like taking one step back after already taken three steps forward.
Originally posted by SprocketUK
reply to post by Shirak
Fancy posting up the schematic you used?
I feel like playing with a soldering iron for a while...edit on 15-8-2011 by SprocketUK because: I'm a spaz
Originally posted by Fromabove
Voltage without amperage means very little. Most metals will pick up a certain amount of energy and show it as voltage, but when you attempt to use it it disappears.
Originally posted by Shirak
Originally posted by Fromabove
Voltage without amperage means very little. Most metals will pick up a certain amount of energy and show it as voltage, but when you attempt to use it it disappears.
Yes this is why several times in this thread I have shown that the circuit has current.. Also I found hooking two circuits in parallel with separate antennas doubled the current output.
Originally posted by Shirak
Originally posted by Fromabove
Voltage without amperage means very little. Most metals will pick up a certain amount of energy and show it as voltage, but when you attempt to use it it disappears.
Yes this is why several times in this thread I have shown that the circuit has current.. Also I found hooking two circuits in parallel with separate antennas doubled the current output.
Originally posted by patternfinder
Originally posted by Shirak
Originally posted by Fromabove
Voltage without amperage means very little. Most metals will pick up a certain amount of energy and show it as voltage, but when you attempt to use it it disappears.
Yes this is why several times in this thread I have shown that the circuit has current.. Also I found hooking two circuits in parallel with separate antennas doubled the current output.
what were you using as a load?
Originally posted by TeslaandLyne
The ultimate end is to take captured charges in the capacitor and
store in a battery. I heard of this years ago on the net in a gold
forum as some one used a line antenna and capacitor to charge
a battery. This type of charge recovery was patented by Tesla
with his usual ground connection for the capacitor.
Parallel capacitor connections increases the capacitance.
Here is a patented way Tesla use to charge a battery.
He focused rays upon an insulated plate that knock out
charges causing the capacitor to react. The beam focus
was a solid metal hemisphere:
www.google.com...
I always wondered how effective the method worked.
I thought of using ball bearings but looks like some are ready
made. The beam focus is used by Tesla on some of his
other devices.
Originally posted by Shirak
So after hearing about this and watching a video on it I wanted to test the design for myself.
My Shopping list.
Shopping list.
4 - Germanium Diodes (1N34)
2 - 100 uF 50V electrolytic Capacitors
2- 0.2 uF 50V ceramic capacitors
Antenna or wire.
I bought extra and bought it all on ebay it was less than 3 dollars for mats for one and I didn't pay freight so win.
anyhoo.
I tested it outdoors near dusk.
I then tested it indoors near a radiant energy source.
The output was 7.07 Volt DC and 0.10 amp.
Anyways made two of these circuits and was wondering if anyone could give me some advice as to what the best way to connect the two in parallel is I am hoping to increase my outdoor output by using more antenna arrays.
edit on 15-8-2011 by Shirak because: Spelling