posted on Mar, 28 2011 @ 09:27 PM
reply to post by bmck12
That's not the mass; that's it's radius. Multiply the density by the volume to find the mass. The volume is, if we assume it to be a perfect
sphere because just anything else is absurdly complicated to calculate, 4/3*pi*r^3. (r=1/2 diameter, by the by.)
And, comparatively, that is extremely small. Let's take your measurement of 62 feet.
The moon is about 11400259 feet in radius. That means that the moon is about 183875 times larger than this asteroid. (I think that ratio should
carry over through once you calculate the volume, but I can't remember and don't care to calculate it right now. The fact remains that this thing
is tiny.)
Let's compare the distances with this in mind:
The moon is .00257 AU's from the Earth. This is
closer than the object you describe, by a bit more than 1.5 times.
This object is incredibly smaller than the moon and significantly farther than it. To have a tidal effect comparable to the moon, this thing would
have to be incredibly dense. Although I am not a scientist, I am inclined to say that it would have to be nearly impossibly dense.
Not the cause.