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Originally posted by grey580
1-3x4+7=?
Discuss.
Originally posted by grey580
1-3x4+7=?
Discuss.
Originally posted by snowspirit
reply to post by grey580
1-3x4+7=?
Answers we have so far:
-4, -18, -1, -15, -5, -22, 18, 0
Originally posted by ^anubis^
reply to post by OutKast Searcher
simple arithmatic
addition and subtraction first than multiplication and division 1-3x4+7 (1-3=-2) (4+7=11) -2x11+-22edit on 14-10-2010 by ^anubis^ because: mispelled
Originally posted by GypsK
okok.... not to mention that my kid is learning this in school as we speak, lol
you think I'm stupid?
do this calculation on a calculator then! (seriously, do it)
Originally posted by OutKast Searcher
reply to post by S.P.Q.R
Nope...everytime I type it into google, excel, windows calculator, SQL....I get -4.
I am pretty sure I'm being Punked...punked by people pretending they have poor math skills...at least I hope that is the case.
Originally posted by S.P.Q.R
Originally posted by grey580
1-3x4+7=?
Discuss.
Right answer is simply '0' i can prove you;
the section '-3*4' is complicated. so i want to consider Y=-3*4 and my equation is now:
1+Y+7 = X (i am considering my result as X)
8+Y = X (now i want to consider Y=3*Z)
8+3Z = X
now multiply equation with X:
8X+3ZX = X" (i want to write 'X^2' as X")
subtract Z" (i mean Z^2) from booth sides of equation:
8X+3XZ-Z" = X"-Z"
X(8+3Z)-Z*Z = X"-Z"
i know Y=3*Z and Y=-3*4; so i can calculate Z=-4. i want to put that Z value to two italic one above:
X(8+3(-4))-(-4)*Z = X"-Z"
we all know (X^2 - Y^2) = (X-Y)*(X+Y) now i want to use that at the right side of my current equation above:
X(8-12)+4Z = (X-Z)*(X+Z)
-4*(X-Z) = (X-Z)*(X+Z)
-4 = (X+Z) (and i already know Z=-4)
-4 = X+(-4)
X=0
mission accomplished
Originally posted by ^anubis^
lol all of the answers are right, depending on what the question tells you to do to solve the problem.