It looks like you're using an Ad Blocker.
Please white-list or disable AboveTopSecret.com in your ad-blocking tool.
Thank you.
Some features of ATS will be disabled while you continue to use an ad-blocker.
Originally posted by tauristercus
Allow me to open this thread by asking you a very simple and straightforward question:
"What keeps the moon in orbit around the earth and the earth in orbit around the sun ?"
* (1). 8 drums were 1 meter diameter X 1.5 meters deep X 3mm sheet iron and weighed 150 kg.
* (2). 4 drums were 0.7 meter diameter X 1 meters deep
* (3). 1 drum was 0.2 meter diameter X 0.3 meters deep
* (4). All trumpets were 3.12 meters X 0.3 meters
Originally posted by atlasastro
reply to post by MegaMind
Hi Megamind.
Thank you for replying to my post.
I did not mean that the OP's equation literally contain the constant G in the equation, but that by using the constants of Time and Radius, that this is merely a substitute or proxy for the G and so the equations contain the constant merely expressed in time and radius. As both Time and Orbit are functions of Gravity, the OP acknowledges this by using centripetal acceleration as K in his equation yet wants to claim that the forces responsible are "fudged" in order to make Newton's calculation's correct.
I hope you see what I mean.
I have enjoyed your posts.
Thanks.
Originally posted by atlasastro
reply to post by MegaMind
... I did not mean that the OP's equation literally contain the constant G in the equation, but that by using the constants of Time and Radius, that this is merely a substitute or proxy for the G and so the equations contain the constant merely expressed in time and radius ...
Originally posted by tauristercus
Originally posted by Phage
reply to post by tauristercus
Your method cannot do so. Without knowing the period and distance you cannot calculate the force.
Without knowing the distance (radius), neither can Newton.