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Originally posted by PositiveVibration
The height maybe impossible to measure, but from left to right is at least 10meters right?
Originally posted by PositiveVibration
...The hight maybe impossible to measure, but from left to right is at least 10meters right?
Originally posted by TeslaandLyne
Well how long is a video frame.
We see three images.
Perhaps 6 to 10 seconds for the passage.
If a bug you might have noticed.
So perhaps the unseen just became revealed
by the camera.
Originally posted by TeslaandLyne
So do we make a triangle of arc to increase the one foot radius at 7 mph to see
the speed at 10 feet and 100 feet and so on to see a required speed at a certain
distance from the lens.
Also the image does have some size that might be considered to see how large
the object would be at a greater distance from the lens.
We might be dealing with a large object at high speed at a few thousand feet.
Although the object is below the clouds that is not unusual for the flight of
the fast UFOs.
Originally posted by TeslaandLyne
Inventors manual says 300 miles per second.
Works on horizontal and vertical forces.
Originally posted by TeslaandLyne
it won't take long
I'd find the arc of the viewing area and see what numbers
work out.
Not doing the math just leaves the event to the naysayers.
ED: Due to the photographic sensitivity of the object, I mean
getting a dark object from so far away, means it is most probably
a black light emitter.
Originally posted by Ross 54
Would the camera, when focused on the distant clouds, show a very nearby (10-50 centimeters) insect with the small, sharp, focused outline we see, or just a wide, soft blur, if anything at all? Ross
Originally posted by TeslaandLyne
We know enough.
Passage at .1 seconds means at perhaps one mile altitude and one mile
for the passage the object goes 10 miles per second.
Bad news for any estimate so agents would rather keep the
object close like a bug.