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Originally posted by nataylor
Yes, it's a poor "fake," if the intent was to fool someone into thinking that was an actual photograph from an Apollo mission. But of course that wasn't the intent. The intent was to build a model to simulate lighting conditions.
Originally posted by FoosM
Originally posted by weedwhacker
reply to post by FoosM
Wow, what a nice, clear defined photo. NO shadow problems with that, looks exactly as it should.
Shouldnt
[atsimg]http://files.abovetopsecret.com/images/member/c7a1e7bdf5bb.gif[/atsimg]
look like
[atsimg]http://files.abovetopsecret.com/images/member/1624dc4112bc.gif[/atsimg]
What does that have to do with anything? Just because something is possible doesn't mean it's true. I could easily Photoshop myself shaking hands with the President in the Oval Office. That doesn't mean all pictures of people shaking hands with the President are fakes. When I've got a plane ticket to Washington DC, a few dozen people who saw me at the White House, videotape of me going in the White House, my signature on the guest log, a commemorative pen given only to people who go to in the Oval Office, AND a picture of me shaking hands with the President in the Oval Office, doesn't it become a little more likely than not that I actually went there, even if such a photo could possibly be faked?
Originally posted by FoosM
All you are showing me is that these photos can be doctored and manufactured easily by NASA and USGS. Which is the whole point.
DJ... you got to be kidding me. You dont see the problem?
In one picture Hadley Mons creates a strong shadow, in the other it doesnt.
Its all from Apollo 15 easy to find for all you Apollo experts. LPI should be bookmarked by now.
Originally posted by nataylor
reply to post by FoosM
Post the original Apollo image numbers so we can figure out when and where the photos were taken.
Sun elevation in degrees: 38
Originally posted by FoosMhave fun!
No shadow:
AS15-82-11052
www.lpi.usra.edu...
Sun elevation in degrees: 39
No shadow:
AS15-82-11075
www.lpi.usra.edu...
Sun elevation in degrees: 38
No shadow:
AS15-82-11116
www.lpi.usra.edu...
Sun elevation in degrees: 30
No shadow
AS15-84-11295
www.lpi.usra.edu...
Peak!
Sun elevation in degrees: 20
Shadow
AS15-85-11404
www.lpi.usra.edu...
Sun elevation in degrees: 20
Shadow
AS15-85-11455
www.lpi.usra.edu...
Sun elevation in degrees: 30
No shadow
AS15-85-11489
www.lpi.usra.edu...
Sun elevation in degrees: 30
No shadow
AS15-85-11511
www.lpi.usra.edu...
Sun elevation in degrees: 21
Shadow
AS15-86-11603
www.lpi.usra.edu...
Sun elevation in degrees: 31
No Shadow
AS15-87-11793
www.lpi.usra.edu...
Sun elevation in degrees: 32
No shadow:
AS15-87-11849
www.lpi.usra.edu...
Sun elevation in degrees: 39
No shadow:
AS15-88-11906
www.lpi.usra.edu...
Sun elevation in degrees: 30
No shadow:
AS15-90-12187
www.lpi.usra.edu...
Sun elevation in degrees: 31
No shadow:
AS15-90-12244
www.lpi.usra.edu...
Sun elevation in degrees: 32
No shadow:
AS15-92-12425
www.lpi.usra.edu...
Originally posted by DJW001
reply to post by FoosM
DJ... you got to be kidding me. You dont see the problem?
In one picture Hadley Mons creates a strong shadow, in the other it doesnt.
Its all from Apollo 15 easy to find for all you Apollo experts. LPI should be bookmarked by now.
For the record, here is a link to a high resolution scan of A15-86-11603. It can be found here. Now the next time you post a photo without a proper link I will notify the Mods.
Now what is it about this picture you don't understand? The astronaut and rover are brightly lit, yet slightly under-exposed. The shadowed side of Hadley is therefore even darker than in properly exposed photos. Am I missing something here?
Sun elevation in degrees: 20
Originally posted by nataylor
Shadow
AS15-85-11404
www.lpi.usra.edu...
Sun elevation in degrees: 20
Shadow
AS15-85-11455
www.lpi.usra.edu...
Sun elevation in degrees: 30
No shadow
AS15-85-11489
www.lpi.usra.edu...
Sun elevation in degrees: 30
No shadow
AS15-85-11511
www.lpi.usra.edu...
Do you understand a change in sun elevation just 20 degrees to 30 degrees means means a shadow on a horizontal surface will decrease in length by 40%? And that on a slope of a mountain of those dimensions, the shadow length can shorten by over 90% with just that 10 degree change in sun elevation?
Originally posted by FoosMHadley in some photos casts a distinct shadow in others it doesnt
Thats impossible considering it is 4.6 km tall and 25 km wide.
You simply cant see such a change when one lunar day takes 27 Earth days!
These photos are BOGUS!
You will have to come up with pseudo science to explain it.
Originally posted by nataylor
Do you understand a change in sun elevation just 20 degrees to 30 degrees means means a shadow on a horizontal surface will decrease in length by 40%? And that on a slope of a mountain of those dimensions, the shadow length can shorten by over 90% with just that 10 degree change in sun elevation?
Originally posted by FoosMHadley in some photos casts a distinct shadow in others it doesnt
Thats impossible considering it is 4.6 km tall and 25 km wide.
You simply cant see such a change when one lunar day takes 27 Earth days!
These photos are BOGUS!
You will have to come up with pseudo science to explain it.
The lunar day is about 656 hours (27 days and 8 hours). During that time, the moon will make a full revolution. So just like here on earth if you go out and look at the sun at 3pm on Wednesday, it will be in about the same position at 3pm on Thursday. One revolution is 360 degrees. So we have 360 degrees per 656 hours, or 0.55 degrees per hour. So a sun elevation change of 10 degrees would take over 18 hours. And what do we find with those photos? They were taken about 20 hours apart, which is exactly what we'd expect!
Originally posted by FoosM
[Now let me get this straight, your saying that the sun moved about 10 degrees over a span of how many days?
Because I thought the sun moved about one degree across the moon every over 27 days.
So how do we get this big 10 degree jump?
Originally posted by nataylor
The lunar day is about 656 hours (27 days and 8 hours). During that time, the moon will make a full revolution. So just like here on earth if you go out and look at the sun at 3pm on Wednesday, it will be in about the same position at 3pm on Thursday. One revolution is 360 degrees. So we have 360 degrees per 656 hours, or 0.55 degrees per hour. So a sun elevation change of 10 degrees would take over 18 hours. And what do we find with those photos? They were taken about 20 hours apart, which is exactly what we'd expect!
Originally posted by FoosM
[Now let me get this straight, your saying that the sun moved about 10 degrees over a span of how many days?
Because I thought the sun moved about one degree across the moon every over 27 days.
So how do we get this big 10 degree jump?edit on 17-11-2010 by nataylor because: (no reason given)
Ill have to give you this round Nat
Originally posted by FoosM
I cant help you understand DJ Tattletale.
That is something you will have to let you brain work out overnight or nights.
This has nothing to do with exposure.
Hadley in some photos casts a distinct shadow in others it doesnt....
This video shows the strange behavior of the LEM in space during its travel from the LCM to the lunar ground. Normally, the LEM should make a parabolic trajectory during which it slowly rotates from a horizontal position to a vertical position all along the trajectory. I explain that it is abnormal for the LEM for go above the LCM in an orbit farther than the one of the LCM, and also to make brutal rotations.
It's a totally abnormal way of guiding it, and yet this is what we see on the Apollo photos.
This video talks about the behavior of the Lem when it goes from the LCM to the moon, and conversely when it comes back from the moon to the LCM.
I have already made a video showing the anomalies of the behavior of the Lem in space, but I had not talked about the return of the Lem to the Lcm.
This time I talk about it more in detail, and I also show the anomalies concerning the return of the Lem to the LCM.