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Originally posted by TheRedneck
In the atmosphere, the carbon dioxide does not combine chemically with other atmospheric components. It is still carbon dioxide.
The second point I think you've missed is the dynamics. Take New Orleans, as an example -- when just the Native Americans lived in the area, the CO2 levels were fairly stable. Then people with permanent settlements moved in and they copped out the trees and drained swamps and redirected the river to make the place liveable. One house took away the equivalent of 3-4 trees plus shrubs plus vegetation converting CO2.
Would that not be factored into the average carbon dioxide level in the atmosphere? If we decrease the planet's ability to sink carbon dioxide, the result is an increase in carbon dioxide. That increase is indeed taken into account, in the average carbon dioxide levels of the atmosphere.
Uhmm... did that help?
Originally posted by 4nsicphd
Conceptually dead wrong. Read Feynman's "Quantum Electrodynamics" to see why. They only allow 4000 characters in a post and it would take far, far more to explain photon - electron interactions, much less the photon - hadron interactions involved. Feynman wrote a book on those too.
FOI, do you mean elastic cross section or total inelastic cross section?And at what energy level? It has only been measured at 100 to 500 eV.
And given the wave-particle duality of a photon, it is utterly meaningless to talk about a cross section.
And you ask how many CO2 atoms there are in a certain area. Absolutely none, zero, nada. CO2 is a molecule, a zero dipole linear molecule. Not an atom. An atom is the fundamental unit of an element. CO2 has one carbon atom and two oxygen atems, bound together covalently.
[edit on 4-12-2009 by 4nsicphd]
Cannot simple experiments determine with a fair level of accuracy how much heat is absorbed by CO2 by shining an exact amount of light through an exact amount of CO2 and then measuring the temperature change?
Originally posted by TheRedneck
Let me rephrase it to be sure. What you are saying is that each component interacts radiatively with nearby components, thus causing any emitted energy to be re-absorbed. Is that close to what you are suggesting?
Now the problem: the lack of data on such interactions. I have finally given up for the moment on finding data and am working on developing equations for this interaction myself. If I can find solid data that makes all this work useless, I will of course defer to it.
Originally posted by jimmyx
uhhmmm......six inches of snow in houston (second time in the past five years), below freezing tempertures...and houston is right on the coast of the caribbean. yup, no climate change here...move along now, we have fossil fuels to burn.
www.youtube.com...
[edit on 5-12-2009 by jimmyx]
Originally posted by jimmyx
uhhmmm......six inches of snow in houston (second time in the past five years), below freezing tempertures...and houston is right on the coast of the caribbean. yup, no climate change here...move along now, we have fossil fuels to burn.
www.youtube.com...
[edit on 5-12-2009 by jimmyx]
Originally posted by Animal
Well there will be no convincing you, and many like you. That really is too bad. I like how you can justify 5% of the worlds population using 30% of the worlds resources.
Yes and no. For instance, sun and water vapor together will create an area of high pressure that will keep more greenhouse gases and pollutants in a local area. That increases the local density of the CO2 and methane and together they act to keep heat in the atmosphere... and so on and so forth.
Source: answers.noaa.gov...
The accepted world record maximum "sea-level equivalent" pressure was observed at Agata Lake (66 degrees 53 minutes N, 93 degrees 28 minutes E) in Siberia at 1200 GMT on 13 December 1968: 31.99 in (1083.3 mb).
Because it's a dynamic system and in order to make estimations they divide the map of the Earth into small sections (I don't know how small, but a square mile or smaller). Because they're doing vector analysis and other types of multivariate analysis, they use supercomputers or supercomputer clusters to get current models (or they used to. I believe they still do, since modeling climate involves so darn many factors that it's a huge number-crunch fest.)
HOWEVER... If you're basing your model only on CO2, you've missed the bulk of the data that should be in your equation.
Originally posted by TheRedneck
reply to post by Byrd
HOWEVER... If you're basing your model only on CO2, you've missed the bulk of the data that should be in your equation.
The bulk?
The following data was taken from cdiac.ornl.gov...
Carbon dioxide (CO2) - 384ppmv
Methane (CH4) - 1865ppbv = 1.865ppmv
Nitrous Oxide (N2O) - 322 ppbv = 0.322ppmv
Tropospheric ozone (O3) - 344ppbv = 0.044ppmv
CFC-11 (trichlorofluoromethane) (CCl3F) - 244pptv = 0.000244ppmv
CFC-12 (CCl2F2) - 538pptv = 0.000539ppmv
CF-113(CCl2FFClF2) - 77pptv = .000077ppmv
HCFC-22(CHClF2) - 206pptv = 0.000206ppmv
And it goes downhill from there. The total amount of other greenhouse gases than carbon dioxide and water vapor add up to less than 2.5ppmv of the atmosphere... less than 1% as much by volume as carbon dioxide alone.
That is not to say they do not have any effect, but it does indicate that their contribution as a greenhouse gas would be much, much less than that of carbon dioxide, and certainly insubstantial as far as radiative forcing goes.
TheRedneck
Originally posted by TheRedneck
reply to post by Byrd
Yes and no. For instance, sun and water vapor together will create an area of high pressure that will keep more greenhouse gases and pollutants in a local area. That increases the local density of the CO2 and methane and together they act to keep heat in the atmosphere... and so on and so forth.
True, but these high pressure areas are both localized and offset by low pressure areas. Isn't what you are putting forth just deviations from the average which in the end cancel each other out? After all, the pressure differences that drive weather are minimal when compared to the average pressure of the atmosphere.