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Originally posted by cogburn
Honestly, I've no idea why anyone would say that a north side approach is aerodynamically impossible.
Originally posted by cogburn
All I want is someone involved to address this one, simple issue.
Why is the plane shown nearly 100ft above the Pentagon in the PDF supplement in direct contradiction to the testimony of Robert Turcios?
Considering witnesses are not able to determine altitude, it is impossible to determine a “pull out” without such data points. Also considering the Navy Annex is roughly 100 feet higher than the Pentagon based on topography alone, very little, if any “pull out”, is needed.
Originally posted by Craig Ranke CIT
Originally posted by cogburn
Why is the plane shown nearly 100ft above the Pentagon in the PDF supplement in direct contradiction to the testimony of Robert Turcios?
Now Robert Turcios admitted that he did not see a flyover OR an impact so I don't know why you think he would be an accurate reference as to the true altitude of the plane when it reached the Pentagon. He admitted his focus was on the "fireball".
The view was obstructed, I could only see the fireball.
No, no I did not see a plane fly over the Pentagon
Originally posted by cogburn
Now turn to page seven. The image on page seven is an impossible flight path as it requires the aircraft to actually strike both the Navy Annex and the ground.
Given the flight path illustrated on page 5 is in contradiction to Turcios's testimony, combined with the fact that the illustration on page 7 is impossible due to the lack of supporting physical evidence, both are absolutely unfounded in reality.
As I said long, long ago in this thread. It's not the math that's incorrect, it's the application.
Are the maths correct? Absolutely. Are the applications of theory correct? Absolutely.
P4T/CIT, in just a few posts prior, begins to justify this contradiction by subjectively eliminating portions of testimony because they are inconvenient to the narrative being presented.
I'll leave it to the silent majority to pass verdict on such behavior.
Are the flight paths aerodynamically possible? For some planes, sure.
Are the flight paths aerodynamically possible and supported by the rest of the volume evidence presented by P4T/CIT? Nope.
This assumption that a north side approach could not have hit the Pentagon is the problem here. Clinging to that notion makes everything else fall apart.
Turcios lost sight of the plane as it dipped towards the bottom of the Pentagon because of the ground, then witnessed the explosion.
Originally posted by 911files
Sagitta Equation
With the proper math in hand, then I will allow ATS readers to check a few of the radius values used in the "paper" and "cartoon" with those derived by real-world sagitta values. I'll check back tomorrow after everyone has had a chance to do their homework and talk radii.
...Besides, someone needs to let 911files know he blew nearly everything on that 4099 foot "radius" and sagitta "calculation" if he worked from the image that he posted.
"911Files" admits our arithmetic is correct for bank angle, but is apparently confused regarding his G Load calculations based on bank angle. I will set him straight here....
The formula we used in the video presentation (which Farmer thinks solves for G load) is:
Θ = arctan ((V^2/r)/11.26)
The above formula does not solve for G load (as "911Files" claims). It solves for bank angle theta (Θ) based on radius and speed. It has nothing to do with G Load.
Even Farmer himself didnt understand it and thought his numbers were off due to NM length and "conversion factor".... Its about time you realized your errors and that you and Farmer were wrong! It only took our release of the tech paper and diagram for JayDuh and Farmer to understand the vectors.
Originally posted by RockHound757
This assumption that a north side approach could not have hit the Pentagon is the problem here. Clinging to that notion makes everything else fall apart.
I let Craig answer that one.
Originally posted by 911files
reply to post by RockHound757
Now here you are quoting people who don't know the difference between the component vector g-force resulting from the turn and the g-load (an aeronautical term). Perhaps you guys will need to brush up on those topics as well.
Originally posted by 911files
You obviously have not read the links and are just wanting to play. G-force does NOT equal G-Load (often called the Load-Factor). I am being generous here. The actual terminology is Load-Factor and it is a dimensionless number and has no acceleration units involved in it at all.
I defined each an every term I used and my g value was clearly defined as centripetal force in terms of g.
"I came up with the same values for bank angle [as P4T], but slightly lower g-force values. I suspect it is in the conversion factors used. I used 6076.1 feet per nautical mile and 32.2 ft/s2 for g." - 911Files, Dec 26, 2008
Do a little homework and I will see ya'll tomorrow.
The actual terminology is Load-Factor and it is a dimensionless number and has no acceleration units involved in it at all.