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Originally posted by ArMaP
This is a more correct representation of the second drawing.
Maybe this will show better what I am trying to explain. The black arrows show the two velocities affecting the blue ball, one that the ball "inherited" from the shuttle and the other the result of the acceleration created by the applying of a force to the ball to make move away.
In that case the ball would have a slightly smaller velocity than the shuttle, because it would have a negative velocity (in direction, not in value) combined with the positive velocity of the shuttle.
Originally posted by Balez
Well that depends on how you wish to see it, will you see momentum as a force?
Thank you Armap. Very nice, and both diagrams are right. Of course momentum is not magically lost by the ball as soon as it leaves the shuttle as Balez believes.
Originally posted by Balez
Well that depends on how you wish to see it, will you see momentum as a force?
There is only one way to see it. Change in momentum is the result of a force. It's all you need to know. What you wrote doesn't make sense.
And you have yet to explain what forces are involved in accelerating these 'dust' particles and causing them to change orbit?
And you have yet to explain what forces are involved in accelerating these 'dust' particles and causing them to change orbit?
Originally posted by WitnessFromAfar
I would add one more factor in, however. Now we need to know the angle of the ejection point in relation to the shuttle. If we're firing 'into the wake' or 'out the rear'. This would determine how much of each force would be distributed on any particles coming out of the ejection stream.
Originally posted by zorgon
LOL Experiments? So tell me again how we will do these experiments in Space?
Originally posted by zorgon
Or at the very least a chamber with LEO gravity simulated and no air?
Originally posted by zorgon
And you have yet to explain what forces are involved in accelerating these 'dust' particles and causing them to change orbit?
Hmmmm
Unless you are stating that the object is travelling with two different momentums and two different trajectories just without any reason what so ever?
Armap's two arrows are two components of the momentum vector. You add them up.
If an object is moving in any reference frame, then it has momentum in that frame. It is important to note that momentum is frame dependent. That is, the same object may have a certain momentum in one frame of reference, but a different amount in another frame. For example, a moving object has momentum in a reference frame fixed to a spot on the ground, while at the same time having 0 momentum in a reference frame attached to the object's center of mass.
The amount of momentum that an object has depends on two physical quantities: the mass and the velocity of the moving object in the frame of reference.
I think some of the problems about momentum, force and velocity we are having here are the result of different definitions from different people, so it may be a good thing if we agree about these definitions before discussing any more, we may be all saying the same thing but using different words.
If an object is moving in any reference frame, then it has momentum in that frame. It is important to note that momentum is frame dependent. That is, the same object may have a certain momentum in one frame of reference, but a different amount in another frame. For example, a moving object has momentum in a reference frame fixed to a spot on the ground, while at the same time having 0 momentum in a reference frame attached to the object's center of mass.
The amount of momentum that an object has depends on two physical quantities: the mass and the velocity of the moving object in the frame of reference.
So, and as waveguide3 said, the relative velocities make a difference, that is why I made two different arrows to show the two different forces responsible for the movement when seen from someone not on the shuttle.
That is why I said "when seen from someone not on the shuttle". For someone not on the shuttle we have to include the force that gave the shuttle its momentum (and the shuttle gave it to all the things attached to or inside it).
Originally posted by Balez
You are still wrong about the force, there were no force active on that ball only momentum, there were one force though, and that force is the force that ejected the ball from the shuttle, on it's already gained momentum from the shuttle.
That is why I said "when seen from someone not on the shuttle". For someone not on the shuttle we have to include the force that gave the shuttle its momentum (and the shuttle gave it to all the things attached to or inside it).
My idea was not to show the forces present at the moment (if it had been then I wouldn't have put the arrows on the second and third parts of the sequences), it was to show the forces that gave those objects (the shuttle and the ball) the energy to keep them with their constant velocities (I also ignored that any force would create an acceleration and not a constant velocity).
Another investigation of Columbia's surroundings made use of the orbiter's Flash Evaporator System (FES). To accomplish this experiment, the crew participated in activating and deactivating the orbiter's water release systems and manually operating the Shuttle's attitude control system jets. This provided a controlled means of studying the distribution of neutral and charged particles in the vicinity of the payload bay during Shuttle water dumps.