200,000 fraudulent votes in Michigan elections

Once Washington Post supported claims of voter fraud. It was in the case of Russian elections. Their article stated:

United Russia’s reported election results are so improbable as to violate Gauss’s groundbreaking work on statistics.

An elaborate analysis of fraud in Russian elections was performed by the analysts from Market Financial.

Let us estimate the total voter fraud in Michigan using their method.

Using the EP distribution one can easily estimate the number of votes above that dictated by normal distribution. Let us continue symmetrically the EP curve beyond 27% - a mirror reflection. The distribution should fall to zero at approximately 50% (x-axis). The difference between the measured EP curve and the imaginary extension is the bias introduced by a control force. On average, there are 400 polling stations in any 0.5% bin after 50% in the EP curve. One has 400x2x50=40,000 polling station with biases.Now we have to evaluate the number of votes. The mean value for the EP distribution is 27%. Then for all polling stations the bias can be estimated as the measured value less 27%. Between 50% and 100% one has 48% on average, i.e. (100%+50%)/2 – 27%. For an average polling station with 1000 voters one has a positive bias of 480 voters. For all 40,000 stations this gives 19,000,000. This figure depends on the average size of polling stations. For 500 voters stations the final number is 9,500,000.

Let us substitute Michigan numbers into the above algorithm.



Using the Obama distribution one can easily estimate the number of votes above that dictated by normal distribution. Let us continue symmetrically the Obama curve beyond50% - a mirror reflection. The distribution should fall to zero at approximately 70% (x-axis). The difference between the measured EP curve and the imaginary extension is the bias introduced by a control force. On average, there are 20 polling stations in any 0.5% bin after 70% in the Obama curve. One has 20x2x30=1,200 polling station with biases.Now we have to evaluate the number of votes. The mean value for the Obama distribution is 50%. Then for all polling stations the bias can be estimated as the measured value less 50%. Between 70% and 100% one has 35% on average, i.e. (100%+70%)/2 – 50%. For an average polling station with 1000 voters one has a positive bias of 350 voters. For all 1,200 stations this gives 420,000. This figure depends on the average size of polling stations. For 500 voters stations the final number is 210,000.

Sorry, but NO FKN fraud.
Machin(es do not commit fraud, but people running them machines do. Guess why no one wants to tackle that, well, they want to go home at night and see their family

America has a fkn Dictator in office and everyone is afraid of him

Remember I said this " FEAR" = fear every alien (american ) regardless

I posted a chinese kung fu movie the other day
the script is to a perfect example of the current pos in the oval office

America has NO right to live by the Constitution of the United States under the pos in the Oval Office, don't believe me, read it. And see what has taken place in the USA in the last 2 years.

Why Washington Post lost any interest in exposing voter fraud?