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originally posted by: dashen
a reply to: Bedlam
so to recap,
1. photons are readily absorbed by sodium in the visual wavelengths.
2. photon absorption drastically changes the chemical properties of an atom momentarily
3. the rods and cones work the way they do because a cone fires with EVERY PHOTON that hits it.
4. regular dermal nerves would fire sporadically and randomly under the influence of a few to several excited Na+ ions
agree or disagree?
originally posted by: dashen
a reply to: Bedlam
lets put it this way. a photon reacting with Na+ would give it different properties.
not necessarily highly reactive ones. for instance i believe a sodium ion would lose its cation properties momentarily before emitting the photon.
originally posted by: Bedlam
I don't know about EVERY PHOTON. I would, in fact, NOT expect them to fire with every photon. Or you'd have every one of them firing non-stop from stray photons in the environment. Rods and cones also require something very special in order to sense light. And that is a specialized pigment that is doing the light detection. Without rhodopsin or a light sensitive color pigment, rods and cones are light insensitive and will NOT fire.
The human eye is very sensitive but can we see a single photon? The answer is that the sensors in the retina can respond to a single photon. However, neural filters only allow a signal to pass to the brain to trigger a conscious response when at least about five to nine arrive within less than 100 ms. If we could consciously see single photons we would experience too much visual "noise" in very low light, so this filter is a necessary adaptation, not a weakness
originally posted by: Bedlam
If you want pair production to occur, the photon that's about to be traded for a particle pair MUST have as much equivalent energy as the mass of an electron and a positron. If you want them to go tearing out of there with some momentum, the photon has to have some extra to contribute to it. A photon with less energy than that needed to form a pair will NEVER form a pair.
The conversation is about whether light from a monitor can stimulate nerves directly. The question at hand from Dashen is whether/how a photon can alter ionic states of metal atoms in/near a neuron, and the last few posts before yours are related to whether a photon can reduce an ion to a metallic state (it can't). You popped up with the interesting observation that pair production could create an electron.
That's true, but it produces a positron as well. And it requires gamma rays. That's not optional. So it seems obvious that your comment was aimed at implying that a photon could cause charge transport. Not only is that wrong, it requires a photon of majestic energy levels. One you won't get from a monitor. Or much of anything else lying about the house, really.
originally posted by: dashen
a reply to: Bedlam
ok now. when a photon pushes a resting electron into an Na+ p shell,
it (the ion) would then behave differently . "charge" as far as ions are concerned are just the way they react chemically.
originally posted by: IlTuoFratello
Got it. e=mc2.
I see. I will continue to come back to this very interesting read.
Your metaphorical analogy regarding the baseball and the baseball bat what was I was if reference to. I suppose it may have been a bit off topic, but I just wanted to note that an electron lost, can be regained, though it would require two high intensity beams/photons to collide, and would also posit a positron.
Okay, okay, carry on. I do not want to derail.
originally posted by: dashen
a reply to: Bedlam
and as far as that burning sensation, no need to call a doctor, stochastic filtering and sensory gating blocks out random, useless, or non patterned nerve firings.
otherwise we would freak out man,with our total perception of reality
Origin[edit]
When an atom or molecule interacts with an electromagnetic wave of frequency scriptstyle[omega], it can undergo a transition from an initial to a final state of energy difference scriptstyle[hbaromega] through the coupling of the electromagnetic field to the transition dipole moment. When this transition is from a lower energy state to a higher energy state, this results in the absorption of a photon. A transition from a higher energy state to a lower energy state results in the emission of a photon. If the charge, scriptstyle[e], is omitted from the electric dipole operator during this calculation, one obtains scriptstyle[mathbf[R]_alpha] as used in oscillator strength.
Your misinterpreting your source if you think it supports the idea that charge is not charge. Charge is charge, in fact this is a fundamental principle of physics.
originally posted by: dashen
a reply to: Bedlam
charge is not charge. its early and im hungover, but i think the absorption and subsequent emission of a photon causes a temporary dipole as the electron falls back to its resting state as seen here
Charge conservation is a physical law that states that the change in the amount of electric charge in any volume of space is exactly equal to the amount of charge flowing into the volume minus the amount of charge flowing out of the volume.
I can't prove a negative. Someone would have to prove to me that it can if they are making that claim, and I've never seen proof of that. My expectation is probably not but if there's evidence otherwise I'd be interested to see it.
originally posted by: dashen
Would a sodium ion having an electron jump into the next valence shell affect its chemical reactivity enough to make A difference