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originally posted by: ImaFungi
a reply to: Arbitrageur
Why does the value c², multiplied by m, equal energy?
The amount of consistently ticked intervals it takes for light to move an amount of consistently distant intervals;
Why does 'multiplying' that relation of intervals, by 'whatever mass is'; lead to 'whatever energy is'?
originally posted by: KrzYma
originally posted by: Arbitrageur
Your Mass is NOT From the Higgs Boson
NICE !!
1:08
"the rules are pretty simple... in order for a particle to exist, it must be colorless, or..white... "
"you can accomplish this in two different ways, you can MAKE tree quarks where each one in a different color..."
HALO ?? is anybody thinking ?? are there any brain activity ??
what a peace of BS !!
if there can be no particle with a color, just colorless, how can there be 3 particles with color that make up an colorless something that can exist ??
MAKE... is the magic work here !!
originally posted by: disk4
I appreciate the responses that I got to my question about the photoelectric effect
however they weren't necessarily definitive proof and that's what I was asking if there was definitive proof
one final question when the photon knocks the electrons loose what happens to the atom is it still the same?
Just one electron short?
that's the part that's confusing me the most is what happens to the atom once it loose it's electron
The wave nature of measuring the particles (or though set theory) allows for superposition. That is two waves can add together to be 0, three waves can add together to be zero, and this happens at any given point or a continuum of points.
That way you can measure whether energy is being created or destroyed or staying the same.
Also velocity is the change in distance over .. time, and speed is the magnitude of that vector .. .
I should note that c^2 in this case comes from the integrating work and it is really a pleasant 'coincidence' that the result is a non-negative number which allows for absolute comparisons.
originally posted by: KrzYma
a reply to: FriedBabelBroccoli
That way you can measure whether energy is being created or destroyed or staying the same.
what energy ?? define energy !!
Also velocity is the change in distance over .. time, and speed is the magnitude of that vector .. .
yeah.. velocity has direction, speed doesn't
I should note that c^2 in this case comes from the integrating work and it is really a pleasant 'coincidence' that the result is a non-negative number which allows for absolute comparisons.
NO.. square makes 2d, cubed 3d
try to multiply a line by a square...
He probably didn't want to introduce the word hadrons since most people don't know what those are, but he means that hadrons must be "colorless", based on adding the "color charge" of quarks, and he did mention protons and neutrons specifically which are well-known types of hadrons.
originally posted by: KrzYma
1:08
"the rules are pretty simple... in order for a particle to exist, it must be colorless, or..white... "
"you can accomplish this in two different ways, you can MAKE tree quarks where each one in a different color..."
HALO ?? is anybody thinking ?? are there any brain activity ??
what a peace of BS !!
if there can be no particle with a color, just colorless, how can there be 3 particles with color that make up an colorless something that can exist ??
You consistently think your failure to understand a model is a problem with the model, as in the above example. It is not. While of course some models have some problems you rarely seem to understand what they are, so stop assuming the problem is with the model and start assuming you don't understand it well enough yet and you might make some progress. Then when you understand the model well enough, you can figure out what the REAL problems are with the model!
MAKE... is the magic work here !!
Among all elementary particles, only e±, μ± and γ are detected directly in the modern detectors. For, e±,γ, calorimeters are used: these particles interact with material having a large atomic numbers creating many more electrons and photons producing what is called an electromagnetic shower. For muons, gas detectors are usually used in association with a tracker (that can be made with silicon detectors) that can measure the trajectory of charged particles thanks to a powerful magnet.
All the other elementary particles are detected through their decay products by combining their energy/momentum in order to measure the invariant mass of the decay products. The comparison of the invariant mass with the nominal mass of the particle give a good indication of the nature of the particle.
In case of the τ lepton, the lifetime is large enough, so that they can fly a few mm before decaying. Hence, by detecting the primary vertex (source of the collision) where the τ has been produced and the decay vertex, we can measure their time of flight. The combination of the time of flight and the invariant mass of the decay products are a good way to identify the τ.
Quarks cannot fly freely and are necessarily "dressed" into hadrons (pions, proton etc). If the energy of the quark is large enough (and this is the case with modern experiment), 1 single quark will produce a large number of hadrons flying roughly in the same direction as the initial quark. This will form a jet of hadrons. Now b quark and to a lesser extent c quark produce respectively B and charmed hadrons that can fly few mm. So again, a jet of hadrons not pointing to the primary vertex is a sign of b or c quark. For u,d,s quarks, they produce jets that cannot be really distinguished (at least with the high energy collisions of nowadays). Gluons produce same kind of jets (but slightly broader). top quark is a bit special: its lifetime is so short that it decays immediately into a b quark plus a W. So the association of a b-jet with a W (see later) is a sign of a t quark. Hadrons contained in the jets are detected with hadron calorimeters.
Z and W bosons have a very short lifetime and decay as soon as they are produced. However their mass is huge compared to (almost) all the other elementary particles. Z can have a clear signature via their leptonic decay Z→e++e−,μ++μ−,τ++τ−. When they decay into quarks qq¯, they produced 2 jets that can be combined to measure the invariant mass (but with a much less good accuracy that with leptonic channel). For W, they can decay into a neutrino and a charged lepton or into qq′¯ producing 2 jets. The neutrinos are not detected and so will appear as a missing energy flow by comparison with the initial energy of the collision. The combination of the magnitude of this missing energy and its direction with the charged lepton give an approximate mass spectrum with a shape that can be used to track the W. With the W hadronic decay (into jets), the combination of jets give also access to the invariant mass.
originally posted by: ImaFungi
We are still waiting for a depiction of what and how the photon itself might be.
originally posted by: Bedlam
Wood. It's a little wooden ball, typically painted yellow.
They aren't painted yellow like the photon because they have charge and the photon has no charge. + charge typically is painted red and -charge is typically painted blue:
originally posted by: ImaFungi
What is the physical difference about the physical body of + charge and - charge?
Fields are man-made models to approximate the behavior of nature. Unlike Santa and Unicorns you can measure field strength at various points in space so the model matches observables regardless of the ontology of the actual behavior of nature.
Either a field is physically real or it is not, if it is not real we may as well talk of santa and unicorns; if it is physically real, then I presume it might be included in your response to the last question; that it is a combination between the physical body of + charge and the physical body of field (and physical body of - charge and the physical body of field) which results in the detectable phenomenon of difference in reaction.
Why do you think they are shown in red and blue? Because they're different.
If there is no physical characteristic that is fundamentally different about + and -, then there would be no need to make the distinction. So I am asking if it is theorized and/or known the physical distinction.
Remove all the iron from the Earth to prove to me that the moon is not held in orbit by magnetism from the iron. See how ridiculous that sounds? Or maybe it doesn't to you. As difficult as that would be, it might actually be more difficult to remove quarks from protons than to remove all the iron from the Earth. In neither case is it really necessary to fulfill the ignorant request.
originally posted by: KrzYma
Show me an experiment where 2 protons collide and produce sub particles and I will change my mind