Jack Burkman: Ron Paul WILL be on GOP ticket

Yes, as they both say, this is a 'bold claim.'

But regardless, it is exciting, and nothing is impossible.

RP 2012!

YEAH BABY!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

reply to post by eleven44


I agree with you my friend.

It is very likely he will be at least vice president, and from there he will have an awesome influence on the country as a whole. Paul would be the wise adviser, the Merlin!

I get just as excited about Ron as the next guy but, you are assuming a lot with that statement. I'm not convinced a Romney led ticket could beat Obama. Which would be a requirement to see VP Paul.

The Ron Paul phenomena is heating up! Not only is Paul getting love from the judge. Neil Covuto is even giving Paul his fair share, Its about time... Republicans must be sobering to the fact that the only way to beat Obama is to put Ron Paul on the ticket, It is the only way, So now the question is: What does the electorate want more. Getting rid of Obama or ending the status quo and business as usual in Washington. To me this is no choice at all...
RP 2012

Is it just me, or would a Ron Paul vice-presidency accomplish NOTHING??

He would be the equivalent of the good angel on the shoulder of Romney, who's already bagged by the corporate/shadow interests.

In other words:

1. They're realizing Clowns 1, 2 or 3 can't win against Obama.
2. They realize they can use Ron Paul without really supporting him.
3. They realize they HAVE TO use Ron Paul to win the election.
4. They can also control Ron Paul much better under their wing than leaving him loose.

So are the voting machines rigged or not, or rigged enough or not if 'they' think they have to do this dance at all to put whoever they want into office?

Or is there really no difference between Obama's controllers and any republican president's controllers and this is all just a big soap opera?

Remember Joe Biden?

He's our current Vice President....he may as well not even exist.